C++循环链接列表 - 删除所有节点

Question

我想删除单循环链表中的所有节点。但我得到了以下错误：

malloc: *** error for object 0x1005068f0: pointer being freed was not allocated 

以下是功能：

void StudentLinkList::removeAll() { 
    StudentData *traversePointer = this->head; 

    while (this->head != nullptr) { 
     this->head = this->head->getNext(); 
     delete traversePointer; 
     traversePointer = nullptr; 
     traversePointer = this->head; 
     this->size--; 
    } 
} 

我就在这行错误：

delete traversePointer; 

我的问题是，为什么traversePointer未分配在while循环如错误所示？

Answer 1

的同时应该是：

while(this->size){ 

当循环完成，则设置这个 - >头= nullptr。没有必要在循环中设置traversePoitner = nullptr。

替代版本（我还没有证实这还），即不依赖于这个 - >尺寸是正确的，只是名单是圆形：

void StudentLinkList::removeAll() { 
    if(this->head == nullptr) 
     return; 
    StudentData *traversePointer = this->head; 
    StudentData *deletePointer; 
    do{ 
     deletePointer = traversePointer; 
     traversePointer = traversePointer->getNext(); 
     delete deletePointer; 
    }while(traversePointer != this->head); 
    this->head = nullptr; 
    this->size = 0; 
} 

你可能想修正这个错误