2013-02-21 56 views
0

我试图显示使用Jquery从网页中的数据库检索项目。但是我的代码没有做到这一点。任何人都会告诉我如何显示数组中的项目。如何使用Jquery显示JSONArray项目

我的代码是:

success: function(data, textStatus, jqXHR) 
     { 
      if(data.success) 
      { 
       for(var i = 0,len=data.length;i<len;i += 1){ 
        if(data.commentInfo[i].success) 
        { 
         var newcommhtml = '<div id="c0'+thecid+'" class="cnew clearfix"> <section class="c-author">'; 
         newcommhtml = newcommhtml + '<h3>Anonymous</h3>'; 
         newcommhtml = newcommhtml + '<span class="pubdate">'+month+' '+day+', '+year+'</span> </section>'; 
         newcommhtml = newcommhtml + '<section class="c-content">'; 
         newcommhtml = newcommhtml + '<img src="images/green-avatar.png" alt="avatar" width="80" height="80" class="ava">'; 
         newcommhtml = newcommhtml + '<p>'+nl2br(data.commentInfo[i].comment)+'</p> </section></div>'; 

         var thelm = "#c0"+thecid; 
         commwrap.append(newcommhtml); 
         $(thelm).hide().fadeIn('slow'); 

         setTimeout(function() { $(thelm).addClass('green'); }, 800); 

         $("#comm").val(""); 
         thecid++; 

        } 
        else 
         { 
         alert("dsdsds"); 
         } 
       } 
        if(errorspan.html() != null) { 
         errorspan.remove(); 
        } 
      } 

      }, 
    error: function(jqXHR, textStatus, errorThrown) 
     { 
     alert("error"+errorThrown); 
     console.log("Something really bad happened " + textStatus); 
     }, 

,并从服务器接收到的响应是:

{"success":true,"commentInfo":[{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"},{"uname":"shyam","comment":"ghg"}]} 

请人帮我....谢谢....

+0

'data'是一个对象,而不是一个阵列,它没有一个'length'属性。 – 2013-02-21 17:28:32

回答

3

data是一个对象不是数组。

如果你想在这是一个数组,你会做数据到目标commentInfo

for (var i = 0; i < data.commentInfo.length; i++) { 
    var item = data.commentInfo[i]; 
} 
+1

可能他也应该测试'if(data.success && data.commentInfo.length){' – Blazemonger 2013-02-21 17:30:40

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