将删除数据插入到表中的触发器

Question

我想创建一个将删除数据插入到备份表中的触发器，我写了这段代码，但它不起作用。当我创建这个触发器时，MYSQL会引发语法错误。我怎样才能得到预期的结果？任何帮助，将不胜感激。

BEGIN 
      IF EXISTS (SELECT * 
     FROM information_schema.tables 
     WHERE table_schema = 'jobportal' 
      AND table_name = 'dlt_jobs' 
     LIMIT 1) THEN 
      create table dlt_jobs (select *,now() as deleted_on from jobs where job_id=OLD.job_id) ; 
      ELSE 
      insert into dlt_jobs (username) values ('something'); 
      END IF; 

     END 

Answer 1

如果u被删除或插入只需添加另一行代码来执行此任务和示例

<?php 
include_once '../dbconnect.php'; 
$error = false; 
if (isset($_POST['btn-signup'])) { 
    // clean user inputs to prevent sql injections 
    $emails = trim($_POST['emails']); 
    $emails = strip_tags($emails); 
    $emails = htmlspecialchars($emails); 
    //basic emails validation 
    if (!filter_var($emails,FILTER_VALIDATE_EMAIL)) { 
    $error = true; 
    $emailsError = "Please enter valid emails address."; 
    } else { 
    // check emails exist or not 
    $query = "SELECT emails FROM newsletter WHERE emails='$emails'"; 
    $result = mysql_query($query); 
    $count = mysql_num_rows($result); 
    if($count!=0){ 
    $error = true; 
    $emailsError = "Provided emails is already in use."; 
    } 
    } 
    // if there's no error, continue to signup 
    if(!$error) { 
    $query = "INSERT INTO newsletter(emails) VALUES('$emails')"; 
    $res = mysql_query($query); 
    if ($res) { 
    $errTyp = "success"; 
    $errMSG = "Successfully registered, you may login now"; 
    unset($emails); 
    } else { 
    $errTyp = "danger"; 
    $errMSG = "Something went wrong, try again later..."; 
    } 
    } 
} 
?>