1
可能重复:
Why is this function returning “undefined”?如何让JavaScript函数返回Ajax结果?
假设我有以下JS功能:
function getTileData(x, y, loc_slug) {
$.ajax({
url: "/sys/map-admin/show-location/"+loc_slug+"/get-tile/"+x+"-"+y+"/",
success: function(data){
alert(data); // Object, that's correct.
**What do I need to make the whole getTileData function return data?**
}
});
}
,我把它叫做另一个函数内的类似
tile = getTileData(1, 2, 'asd');
alert(tile); // undefined