Python 3：将2个元素列表到字典

Question

Python3 OMG，对于可能以这种或那种方式经常重复提出的问题感到抱歉。对我来说，操纵名单一直就像一个黑匣子的头痛，我一直在争斗一个小时，没有结果。

我有形式的列表：

[('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')] 

我想变成一个可迭代的字典这个（是我，然后批量插入作为使用pymongo文件），因此它看起来像这样：

new_posts = [{"sender": "John", 
       "email": "first@email.com"}, 
       {"sender": "John", 
       "email": "second@email.com"}, 
       {"sender": "Jack", 
       "email": "third@email.com"}] 

这将如何以易于阅读和有效的方式实现？

Answer 1

您可以尝试

>>> a = [('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')] 
>>> [dict([('sender', x[0]), ('email',x[1])]) for x in a] 
[{'sender': 'John', 'email': 'first@email.com'}, {'sender': 'John', 'email': 'second@email.com'}, {'sender': 'Jack', 'email': 'third@email.com'}] 

这将转换列表与dict

Answer 2

your_list = [('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')] 
your_result = [{'sender': sender, 'email': email} for sender, email in your_list] 

Answer 3

data = [('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')] 
new_posts = [] 
for i in range(len(data)): 
    new_post = {} 
    new_post["sender"] = data[i][0] 
    new_post["email"] = data[i][1] 
    new_posts.append(new_post) 

解决它的另一种方式..