如何在使用Spring-WS时在客户端动态地设置自定义HTTP头(不是SOAP头)?使用Spring-WS客户端动态设置自定义HTTP头
回答
public class AddHttpHeaderInterceptor implements ClientInterceptor {
public boolean handleFault(MessageContext messageContext)
throws WebServiceClientException {
return true;
}
public boolean handleRequest(MessageContext messageContext)
throws WebServiceClientException {
TransportContext context = TransportContextHolder.getTransportContext();
CommonsHttpConnection connection = (CommonsHttpConnection) context.getConnection();
PostMethod postMethod = connection.getPostMethod();
postMethod.addRequestHeader("fsreqid", "123456");
return true;
}
public boolean handleResponse(MessageContext messageContext)
throws WebServiceClientException {
return true;
}
}
配置:
<bean id="webServiceTemplate" class="org.springframework.ws.client.core.WebServiceTemplate">
...
<property name="interceptors">
<list>
<bean class="com.blah.AddHttpHeaderInterceptor" />
</list>
</property>
</bean>
ClientInterceptor
伟大工程静态标头值。但是当每个请求应用不同的值时,不可能使用它。在这种情况下,WebServiceMessageCallback
有帮助:
final String dynamicParameter = //...
webServiceOperations.marshalSendAndReceive(request,
new WebServiceMessageCallback() {
void doWithMessage(WebServiceMessage message) {
TransportContext context = TransportContextHolder.getTransportContext();
CommonsHttpConnection connection = (CommonsHttpConnection) context.getConnection();
PostMethod postMethod = connection.getPostMethod();
postMethod.addRequestHeader("fsreqid", dynamicParameter);
}
}
该解决方案比使用客户端拦截器更灵活。恕我直言,它应该是首选。 – 2013-09-14 10:27:00
我得到以下异常 java.lang.ClassCastException: 在这条线context.getConnection() org.springframework.ws.transport.http.HttpServletConnection不能转换为org.springframework.ws.transport.http .CommonsHttpConnection – 2014-05-03 07:19:38
仅供参考,'org.springframework.ws.transport.http.CommonsHttpConnection'已被弃用,以支持'org.springframework.ws.transport.http.HttpComponentsConnection'。 – ZeroOne 2015-05-20 14:18:03
以下片段已用Spring 4.0进行过测试。它附加一个WebServiceMessageCallback
到org.springframework.ws.client.core.WebServiceTemplate
final String DYNAMICVALUE = "myDynamo";
WebServiceMessageCallback wsCallback = new WebServiceMessageCallback() {
public void doWithMessage(WebServiceMessage message) {
try {
SoapMessage soapMessage = (SoapMessage)message;
SoapHeader header = soapMessage.getSoapHeader();
header.addAttribute(new QName("myHeaderElement"), DYNAMICVALUE);
} catch (Exception e) {
e.printStackTrace();
}
}
};
JAXBElement<MyWsResponse> response = (JAXBElement<MyWsResponse>)
wsTemplate.marshalSendAndReceive(MyWsOP, wsCallback);
的问题是“你如何设置自定义HTTP头(不是SOAP头)“,但是这个答案实际上增加了一个SOAP头,而不是一个HTTP头。 – ZeroOne 2015-05-20 13:44:13
Spring的webServiceTemplate.marshalSendAndReceive(request)方法内部使用HttpComponentsMessageSender到通过网络发送SOAP消息,这还使用WebServiceConnection使与服务器的HTTP连接。你所要做的就是编写你自己定制的HttpComponentsMessageSender并在postMethod中设置cookie。
Custome发送代码:
package com.swap.ws.sender;
import java.io.IOException;
import java.net.URI;
import javax.annotation.Resource;
import org.apache.http.client.methods.HttpPost;
import org.apache.log4j.Logger;
import org.springframework.stereotype.Service;
import org.springframework.ws.transport.WebServiceConnect ion;
import org.springframework.ws.transport.http.HttpComponen tsConnection;
/**
*
* @author swapnil Z
*/
@Service("urlMessageSender")
public class CustomHttpComponentsMessageSender extends
org.springframework.ws.transport.http.HttpComponen tsMessageSender {
private static Logger _logger = Logger.getLogger("");
@Override
public WebServiceConnection createConnection(URI uri) throws IOException {
String cookie = null;
HttpComponentsConnection conn = (HttpComponentsConnection) super
.createConnection(uri);
HttpPost postMethod = conn.getHttpPost();
cookie = "<Your Custom Cookie>";
postMethod.addHeader("Cookie", cookie);
return conn;
}
}
Spring配置文件:
<bean id="messageFactory" class="org.springframework.ws.soap.saaj.SaajSoapMe ssageFactory" />
<bean id="marshaller" class="org.springframework.oxm.jaxb.Jaxb2Marshalle r">
<property name="contextPath" value="com.swap.provision" />
</bean>
<bean id="webServiceTemplate" class="org.springframework.ws.client.core.WebServi ceTemplate">
<constructor-arg ref="messageFactory" />
<property name="marshaller" ref="marshaller"></property>
<property name="unmarshaller" ref="marshaller"></property>
<property name="messageSender" ref="urlMessageSender"/>
<property name="defaultUri" value=<Server URL> />
</bean>
此我简单地得到豆webServiceTemplate并调用marshalSendAndReceive方法后。因此,在进行HTTP调用之前,每个请求都会设置自定义cookie。
当使用弹簧一体化3和弹簧一体化-WS,以下代码可被用于处理该请求:
public boolean handleRequest(MessageContext messageContext)
throws WebServiceClientException {
TransportContext context = TransportContextHolder.getTransportContext();
HttpUrlConnection connection = (HttpUrlConnection) context
.getConnection();
connection.getConnection().addRequestProperty("HEADERNAME",
"HEADERVALUE");
return true;
}
拦截器可以连接到所述出站网关以下列方式:
<ws:outbound-gateway ...
interceptor="addPasswordHeaderInterceptor" >
</ws:outbound-gateway>
<bean id="addPasswordHeaderInterceptor class="com.yourfirm.YourHttpInterceptor" />
实际上,它是@Tomasz的答案的更新版本,但提供了一个新的Spring-WS API,Java 8快捷方式,并且关心用单独的方法创建WebServiceMessageCallback
实例。
我相信这是更明显和自给自足的。
final class Service extends WebServiceGatewaySupport {
/**
* @param URL the URI to send the message to
* @param payload the object to marshal into the request message payload
* @param headers HTTP headers to add to the request
*/
public Object performRequestWithHeaders(String URL, Object payload, Map<String, String> headers) {
return getWebServiceTemplate()
.marshalSendAndReceive(URL, payload, getRequestCallback(headers));
}
/**
* Returns a {@code WebServiceMessageCallback} instance with custom HTTP headers.
*/
private WebServiceMessageCallback getRequestCallback(Map<String, String> headers) {
return message -> {
TransportContext context = TransportContextHolder.getTransportContext();
HttpUrlConnection connection = (HttpUrlConnection)context.getConnection();
addHeadersToConnection(connection, headers);
};
}
/**
* Adds all headers from the {@code headers} to the {@code connection}.
*/
private void addHeadersToConnection(HttpUrlConnection connection, Map<String, String> headers){
headers.forEach((name, value) -> {
try {
connection.addRequestHeader(name, value);
} catch (IOException e) {
e.printStackTrace(); // or whatever you want
}
});
}
}
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对于将来的用户来说,好的答案是使用HttpComponentsConnection而不是CommonsHttpConnection,因为它已被弃用。 – dardo 2012-07-02 20:13:38
运行JUnit测试时工作吗?在我的情况下,它并不是因为'context.getConnection()'返回'MockSenderConnection'。我正在使用'MockWebServiceServer'进行单元测试。 – Gooseman 2015-12-31 00:21:00