如何停止整个循环？

Question

我在python下面的循环中遇到问题。

只要totalin = 4，它不会停止，但只有当scorein的整个循环结束时才会停止。 （即THRID环）

例如，如果在scorein编号2的totalout = 4，它运行循环，直到它达到10

#global value 
totalturn=0 
totalscorein=0 
totalout=0 

def main 

    numberofturn=int(input("Number of score:")) 

    no_turn=['1','2','3','4','5','6','7','8','9','10'] 
    #while loop condition  
    while totalturn<numberofturn and totalout<10: 

      #increasement 
      totalscore+=1 

      #for loop for score 
      for t in range(1,numberofturn+1): 
       turns=s*1 

       print("\n\n\nThe turn"+no_turn[t]+":",turns) 

       #for loop for number to appear from list 
       for c in range (10): 

        #list for random number to appear 
        numscore = ['1','2','3','4','5','6','7','8','9','o'] 

        #random choice from numscore list to appear 
        from random import choice 
        scorein=choice(numscore) 

        print ("\n\nScores :",scorein) 




        if scorein.isdigit(): 
         totalscorein=totalscorein+int(scorein)    


        if scorein.isalpha(): 
         totalout+=1 



        if totalturn==numberofturn: 
         print("\nTotal turn played:",totalturn) 


        elif totalout==4: 

         print("\nTotal turns played",totalturn) 
         break 

        else: 

         print("") 

Answer 1

你想的break打出来的3个循环的？我猜你是从问题

在这种情况下的标题来判断，因为它是函数的结尾，你可以只用return

Answer 2

尝试改变and操作者or。这似乎是你想要的。

while totalscore<numberofscore or totalout<10: