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我使用Spring 4在Tomcat 8 JDK 8如何传入URI请求定制RequestObject绑定在Spring MVC 4
控制器:
@RestController
public class MyController {
@RequestMapping(value = "/abc/{id}", method = RequestMethod.GET)
public ResponseEntity<MyResponse> myMethod(@PathVariable("id") String id,
@RequestParam(value = "add", required = false, defaultValue = "1") String add,
@RequestParam(value = "sub", required = false, defaultValue = "1") String sub,
@RequestParam(value = "mul", required = false, defaultValue = "1") String mul,
@RequestParam(value = "div", required = false, defaultValue = "1") String div) {
MyRequest request = new MyRequest();
request.setId(id);
request.setAdd(add);
request.setSub(sub);
request.setMul(mul);
request.setDiv(div);
// call service implementation..
service.myMethodImpl(request);
}
所以基本上,我的URI看起来像这样: /ABC/100 =添加10 &分= 10 & MUL = 10 & DIV = 10
是否有任何绑定/ API /用SpringMVC中可获得的注释,所以我不必MyRequest手动绑定?
可能重复的自动绑定这些值发送的请求参数[Spring MVC:复杂对象作为GET @RequestParam](http://stackoverflow.com/questions/16942193/spring-mvc-complex-object-as-get-requestparam) –
@ dustin.schultz谢谢。我应该删除我的帖子,如果它是重复的? –