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我确定这很简单,但我没有很好的计算出错的地方。我正在创建一个空阵列(位置),用getPartnerLocations
函数中的位置对象填充它,然后尝试使用drop
函数绘制地图上的位置。我遇到的问题是在drop
函数中,位置数组中有东西的地方返回的长度为零,因此循环不起作用。任何关于这里发生的提示或想法将不胜感激。Javascript数组显示长度为0时的长度
var markers = [];
var locations = [];
var iterator = 0;
var map;
var geocoder;
var newYork = new google.maps.LatLng(40.7143528, -74.0059731);
function initialize() {
var mapOptions = {
zoom: 12,
mapTypeId: google.maps.MapTypeId.ROADMAP,
center: newYork
};
map = new google.maps.Map(document.getElementById("map_canvas"),mapOptions);
}
function getPartnerLocations() {
geocoder = new google.maps.Geocoder();
$('.partner').each(function(index){
var street = $('.partner-streetaddress',this).text();
var city = $('.partner-city',this).text();
var state = $('.partner-state',this).text();
var country = $('.partner-country',this).text();
var address = street + ', ' + city + ', ' + state + ', ' + country;
geocoder.geocode({ 'address': address}, function(results, status)
{
if (status == google.maps.GeocoderStatus.OK)
{
locations.push(results[0].geometry.location);
console.log(locations[index]);
}
else
{
console.log('failed to geocode address: ' + address);
}
});
});
initialize();
drop();
}
function addMarker() {
console.log('add marker function');
markers.push(new google.maps.Marker({
position: locations[iterator],
map: map,
draggable: false,
animation: google.maps.Animation.DROP
}));
iterator++;
}
function drop()
{
console.log(locations.length);
for (var i = 0; i < locations.length; i++) {
setTimeout(function() {
addMarker();
}, i * 200);
}
}
getPartnerLocations();
是否可以在http://jsfiddle.net/上发布精简版演示? – 2010-12-12 19:56:09