使用特定值计算函数调用的次数

Question

我想用数组中的键创建表。有没有一种简单的方法来做到这一点。

int array1[] = {1,5,3,8,9,11}; 
// table[1] 
// table[5] 
// table[3] 

int count(int a) 
{ 

    //a is one of the values in array. array1[] = {1,5,3,8,9,11}; 
    // for ex 3. 
    // I have to figure out how many times this function was called with what values 1/5/3/8/9/11 
    table[3]++; 
} 

Answer 1

一个简单的代码

#include<stdio.h> 
int n = 6; //number of elements in array1 
int array1[] = {1,3,5,8,9,11}; 
int *funCount;//Count of elements in array1 
int count(int a) 
{ 
    int i; 
    for(i = 0; i < n; i++) 
    if(a == array1[i]) 
     break; 
    funCount[i]++; 
} 

int main() 
{ 
    funCount = (int*)calloc(n, sizeof(int)); 
    int i; 
    count(1); 
    count(3); 
    count(5); 
    count(8); 
    count(9); 
    count(11); 
    for(i = 0; i < n; i++) 
    printf("%d ",funCount[i]); 
    return 0; 
} 

这种做法是好的，如果你array1将是小！ 否则我会建议你使用哈希