2010-07-07 111 views
2

我一直试图摆脱使用DECODE来转换Oracle 11g中的行,其中有一个方便的PIVOT功能。但我可能已经发现了一个限制:Oracle PIVOT,两次?

我想为基表中的每个值返回2列。就像:

SELECT somethingId, splitId1, splitName1, splitId2, splitName2 
FROM (SELECT somethingId, splitId 
     FROM SOMETHING JOIN SPLIT ON ...) 
     PIVOT (MAX(splitId) FOR displayOrder IN (1 AS splitId1, 2 AS splitId2), 
       MAX(splitName) FOR displayOrder IN (1 AS splitName1, 2 as splitName2) 
      ) 

我可以用DECODE做到这一点,但我不能摔跤的语法,让我用PIVOT做。这甚至有可能吗?似乎这个函数不会太难处理。

编辑:是StackOverflow可能不是正确的SQL溢出问题?

编辑:任何人在那里?

+0

来吧,有没有是或否的答案?我在Oracle SQL的错误论坛上? – orbfish 2010-07-08 14:41:24

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直到创建了http://area51.stackexchange.com/proposals/4260/databases或http://area51.stackexchange.com/proposals/6223/oracle-databases,您才能找到合适的位置。 – 2010-11-09 15:05:41

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不幸的是,PIVOT在Oracle中是非常新的,似乎这里的大多数人都不知道回答你的问题。你如何尝试发布到forums.oracle.com?更多的Oracle专家去那里比来这里。 – 2010-11-09 15:14:18

回答

2

oracle-developer.net它会出现,它可以这样做:

SELECT somethingId, splitId1, splitName1, splitId2, splitName2 
FROM (SELECT somethingId, splitId 
     FROM SOMETHING JOIN SPLIT ON ...) 
     PIVOT (MAX(splitId) , 
       MAX(splitName) 
       FOR displayOrder IN (1 AS splitName1, 2 as splitName2) 
      ) 
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就是这样,忘记了先前接受。谢谢! – orbfish 2014-01-21 18:45:21

1

我不知道你提供了什么样的数据,或者你想要什么。也许如果您发布的查询的解码版本返回您正在查找的数据和/或源数据的定义,我们可以更好地回答您的问题。这样的事情将是有益的:

create table something (somethingId Number(3), displayOrder Number(3) 
    , splitID Number(3));    
insert into something values (1, 1, 10); 
insert into something values (2, 1, 11); 
insert into something values (3, 1, 12); 
insert into something values (4, 1, 13); 
insert into something values (5, 2, 14); 
insert into something values (6, 2, 15); 
insert into something values (7, 2, 16); 

create table split (SplitID Number(3), SplitName Varchar2(30)); 
insert into split values (10, 'Bob'); 
insert into split values (11, 'Carrie'); 
insert into split values (12, 'Alice'); 
insert into split values (13, 'Timothy'); 
insert into split values (14, 'Sue'); 
insert into split values (15, 'Peter'); 
insert into split values (16, 'Adam'); 

SELECT * 
FROM (
    SELECT somethingID, displayOrder, so.SplitID, sp.splitname 
     FROM SOMETHING so JOIN SPLIT sp ON so.splitID = sp.SplitID 
) 
PIVOT (MAX(splitId) id, MAX(splitName) name 
    FOR (displayOrder, displayOrder) IN ((1, 1) AS split, (2, 2) as splitname) 
);