它陷入了无限循环

Question

不知道为什么我的代码被无限循环捕获..也许我写的代码错了？或缩进？ 输出没有给出任何错误

public class HelloWorld 
{ 
    public static void main(String[] args) 
    { 
    //Not sure if it's a better way but I did this way: 
final int TRIES = 5; 
int heads = 0; 
for(int i=0; i<=TRIES; i++) 
{ 
    Scanner input = new Scanner(System.in); 
    System.out.print("Do you wanna continue? Y or N? "); 
    char c = input.next().charAt(0); 
    c = Character.toUpperCase(c); 
    if(c =='y'){ 
    int r = (int) Math.random * 2) + 1; //A number between 1 & 2 

     if(r == 1) 
     { 
     System.out.print("heads"); 
     heads++; 
     } 
     else{ 
     System.out.print("Lost"); 
     } 
    } 

    else{ 
     System.out.print(heads); 
    } 
    } 
} 

}

Answer 1

我也不清楚，但我认为这个代码应该很好地工作：

import java.util.Scanner; 
import java.util.Random; 
public class HelloWorld { 
    public static void main(String[] args) { 
     //Not sure if it's a better way but I did this way: 
     final int TRIES = 5; 
     int heads = 0; 
     for(int i=0; i<=TRIES; i++) { 
      Scanner input = new Scanner(System.in); 
      System.out.print("Do you wanna continue? Y or N? "); 
      char c = input.next().charAt(0); 
      c = Character.toUpperCase(c); 
      if(c =='Y') { 
       int r = (int) (Math.random() * 2) + 1; //A number between 1 & 2 
       if(r == 1) { 
        System.out.println("heads"); 
        heads++; 
       } else { 
        System.out.println("Lost"); 
       } 
      } else { 
       System.out.print(heads); 
      } 
     } 
    } 
} 

Answer 2

public class HelloWorld 
{ 
    public static void main(String[] args) 
    { 
     //Not sure if it's a better way but I did this way: 
     final int TRIES = 5; 
     int heads = 0; 
     for(int i=0; i<=TRIES; i++) 
     { 
      Scanner input = new Scanner(System.in); 
      System.out.print("Do you wanna continue? Y or N? "); 
      char c = input.next().charAt(0); 
      c = Character.toUpperCase(c); 
      if(c =='Y'){ 
       int r = (int) (Math.random() * 2) + 1; //A number between 1 & 2 

       if(r == 1) 
       { 
        System.out.println("heads"); 
        heads++; 
       } 
       else{ 
        System.out.println("Lost"); 
       } 
      } 

      else{ 
       System.out.println(heads); 
       break; 
      } 
     } 
    } 

} 

我不知道是什么你试图实现，但是这个代码编译，而且当你说你不想继续时，它会停止循环。使用休息不是最好的做法，但它有效。它仍然只会要求最多5次，因为这是您放入的限制（由TRIES变量给出）。如果你想运行一个无限循环停止，当用户不希望继续下去，你migth想用一个布尔变量，一段时间，像这样：你正变成输入字符

boolean stop = false; 
    while(!stop) 
    { 
     Scanner input = new Scanner(System.in); 
     System.out.print("Do you wanna continue? Y or N? "); 
     char c = input.next().charAt(0); 
     c = Character.toUpperCase(c); 
     if(c =='Y'){ 
      int r = (int) (Math.random() * 2) + 1; //A number between 1 & 2 

      if(r == 1) 
      { 
       System.out.println("heads"); 
       heads++; 
      } 
      else{ 
       System.out.println("Lost"); 
      } 
     } 

     else{ 
      System.out.println(heads); 
      stop=true; 
     } 

注大写，然后将它压缩到'y'，这将永远是错误的。