颠倒NHibernate查询的逻辑

Question

我已经使用NHibernate构建了以下查询，它将为我提供包含给定页面（由页面id引用）的MenuView项目的集合。

// Only retrieve the required properties from Menu object 
ProjectionList menuViewProjections = Projections.ProjectionList() 
    .Add(Projections.Property("ID"), "ID") 
    .Add(Projections.Property("Name"), "Name") 
    .Add(Projections.Property("Description"), "Description"); 

var menus = session.CreateCriteria(typeof(Menu)) 
    // Only menu's that are editable 
    .Add(Restrictions.Eq("IsEditable", true)) 

    // Only project required properties 
    .SetProjection(menuViewProjections) 

    // Only menu's that contain this page (Menu object has IList<Page> property called 'Pages') 
    .CreateCriteria("Pages") 
    // Restrict to menu's containing the pages with an id of the specified value 
    .Add(Restrictions.Eq("ID", pageId)) 

    // Transform results into required, light-weight, view objects 
    .SetResultTransformer(Transformers.AliasToBean(typeof(MenuView))) 
    .List<MenuView>(); 

这工作正常;然而，现在我想做相反的事情：我想查询所有可编辑菜单对象，其中不包含包含具有指定ID的页面。迄今为止，我还没有找到解决方案。我还以为上面的查询的网页部分的简单颠倒就足够导致：

// Only retrieve the required properties from Menu object 
ProjectionList menuViewProjections = Projections.ProjectionList() 
    .Add(Projections.Property("ID"), "ID") 
    .Add(Projections.Property("Name"), "Name") 
    .Add(Projections.Property("Description"), "Description"); 

var menus = session.CreateCriteria(typeof(Menu)) 
    // Only menu's that are editable 
    .Add(Restrictions.Eq("IsEditable", true)) 

    // Only project required properties 
    .SetProjection(menuViewProjections) 

    // Only retrieve menus that do NOT contain this referenced page 
    .CreateCriteria("Pages") 
    .Add(Restrictions.Not(Restrictions.Eq("ID", pageId))) 

    // Transform results into required view objects 
    .SetResultTransformer(Transformers.AliasToBean(typeof(MenuView))) 
    .List<MenuView>(); 

但是，这会导致下面的SQL：

SELECT this_.ID   as y0_, 
    this_.Name  as y1_, 
    this_.Description as y2_ 
FROM [Menu] this_ 
     inner join PagesInMenu pages3_ 
     on this_.ID = pages3_.MenuID 
     inner join [Page] page1_ 
     on pages3_.PageID = page1_.ID 
WHERE this_.IsEditable = 1 /* @p0 */ 
     and not (page1_.ID = 8 /* @p1 */) 

这仍然是返回菜单的结果做的项目包含一个id为8的页面。为什么逻辑的这种简单逆转在代码方面并不那么简单？

[更新] 从Firo的建议，建议的查询更改;

// Only retrieve menus that do NOT contain this referenced page 
.CreateCriteria("Pages") 
.Add(Subqueries.PropertyNotIn("Id", querymenuItemswithPage)) <--- query you have would be here 

现在生成下面的sql语句;

SELECT this_.ID   as y0_, 
     this_.Name  as y1_, 
     this_.Description as y2_ 
FROM [Menu] this_ 
     inner join PagesInMenu pages3_ 
     on this_.ID = pages3_.MenuID 
     inner join [Page] page1_ 
     on pages3_.PageID = page1_.ID 
WHERE this_.IsEditable = 1 /* @p0 */ 
     and page1_.ID not in (SELECT this_0_.ID as y0_ 
          FROM [Page] this_0_ 
          WHERE this_0_.ID = 1 /* @p1 */ 

）

起初似乎正是我想要的，但不幸的是（可能是由于我加入的理解差）仍然没有回来完全是我想要的。给出下面的表

菜单

然后的PagesInMenu联接表（具有WHERE子句WHERE PAGEID = 1）

我们可以看到ID为1的页面在菜单5和6中没有被引用。我期待有问题的查询仅返回单行，这将是编号，姓名，并用5号菜单的说明，因为这是第1页是不列入和是编辑

相反，只有菜单新的查询返回;

我已经越过了被返回，但不应该成为所有行。这里发生了什么 ！？

Answer 1

更新：

• 去除.CreateCriteria("Pages")

• 添加子查询

  var querymenuItemswithPage = DetachedCriteria.For<Menu>() 
  .CreateCriteria("Pages") 
      .Add(Restrictions.Eq("ID", pageId)) 
  .SetProjection(Projections.Id()) 
  
  // Only retrieve the required properties from Menu object 
  ProjectionList menuViewProjections = Projections.ProjectionList() 
      .Add(Projections.Property("ID"), "ID") 
      .Add(Projections.Property("Name"), "Name") 
      .Add(Projections.Property("Description"), "Description"); 
  
  var menus = session.CreateCriteria(typeof(Menu)) 
      // Only menu's that are editable 
      .Add(Restrictions.Eq("IsEditable", true)) 
  
      // Only project required properties 
      .SetProjection(menuViewProjections) 
  
      // Only retrieve menus that do NOT contain this referenced page 
      .Add(Subqueries.PropertyNotIn("Id", querymenuItemswithPage)) 
  
      // Transform results into required view objects 
      .SetResultTransformer(Transformers.AliasToBean(typeof(MenuView))) 
      .List<MenuView>();