斯威夫特3我的代码游戏无法正常工作

Question

如果我触摸除按钮之外的游戏崩溃。我能做什么？如何？我想忽略除按钮之外的所有触摸。我怎样才能做到这一点？ 这里是我的touchesBegan：

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) { 
    let touch = touches.first 
    if let location = touch?.location(in: self), 
     let node = self.nodes(at: location).first { 

     var player = SKSpriteNode() 

     if node.name == "BlueButton" { 
      player = playerB 
      playerB.isHidden = false 

     } else if node.name == "RedButton" { 
      player = playerR 
      playerR.isHidden = false 

     } else if node.name == "YellowButton" { 
      player = playerY 
      playerY.isHidden = false 

     } else if node.name == "GreenButton" { 
      player = playerG 
      playerG.isHidden = false 

     } 
     for sprite in [playerB, playerW, playerR, playerY, playerG] { 
      sprite?.removeFromParent() 
     } 
     player.position = CGPoint(x: 0, y: -60) 
     addChild(player) 
    } 

} 

这里是我的touchesEnded功能

override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent?) { 
    addChild(playerW) 
    playerB.removeFromParent() 
    playerR.removeFromParent() 
    playerY.removeFromParent() 
    playerG.removeFromParent() 

} 

Answer 1

从我的其他答案的讨论我猜你的touchesBegan的复杂性导致你偶尔添加一个以上的player-sprite版本。下面应该只在一个时间这应该更容易避免因精灵精灵覆盖等意想不到的联系人添加每个playerSprite 一次只有一个...

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) { 
    let touch = touches.first 
    if let location = touch?.location(in: self), 
     let node = self.nodes(at: location).first { 

     var player = SKSpriteNode() 

     if node.name == "BlueButton" { 
      player = playerB 
     } else if node.name == "RedButton" { 
      player = playerR 
     } else if node.name == "YellowButton" { 
      player = playerY 
     } else if node.name == "GreenButton" { 
      player = playerG 
     } 
     for sprite in [playerB, playerW, playerR, playerY, playerG] { 
      sprite.removeFromParent() 
     } 
     player.position = CGPoint(x: 0, y: -50) 
     addChild(player) 
    } 
} 

Answer 2

我觉得这个条件

if firstBody.node?.name == "BLUE" && secondBody.node?.name == "BLUEBLOCK" || 
    firstBody.node?.name == "RED" && secondBody.node?.name == "REDBLOCK" || 
    firstBody.node?.name == "YELLOW" && secondBody.node?.name == "YELLOWBLOCK" && 
    firstBody.node?.name == "GREEN" && secondBody.node?.name == "GREENBLOCK" 

应该看起来像

if (firstBody.node?.name == "BLUE" && secondBody.node?.name == "BLUEBLOCK") || 
    (firstBody.node?.name == "RED" && secondBody.node?.name == "REDBLOCK") || 
    (firstBody.node?.name == "YELLOW" && secondBody.node?.name == "YELLOWBLOCK") || 
    (firstBody.node?.name == "GREEN" && secondBody.node?.name == "GREENBLOCK") 

它STIL我看起来很丑，但必须工作

Answer 3

好的，坦率地说它有点乱，特别是didBeginContact函数。如果我正确地读了你的意图，它应该是这样的：

• 任何与“白色”块的联系应该结束游戏。
• 对于其他颜色的所有接触，但一个特定颜色应结束游戏。
• 联系与具体颜色应该增加得分。

如果这确实是我们的目标对像下面可能应该工作，但我还是会建议进一步重构，以避免对古怪的字符串匹配的基础游戏逻辑的这样一个重要组成部分：

func didBegin(_ contact: SKPhysicsContact) { 
    guard let nodeA = contact.bodyA.node else { 
     // this and the one blow are good places to add a breakpoint to inspect what's going on if still having problems 
     return 
    } 
    guard let nodeB = contact.bodyB.node else { 
     return 
    } 

    // Some Bools to make the below logic more readable 
    let blueContacted = nodeA.name == "BLUEBLOCK" || nodeB.name == "BLUEBLOCK" 
    let redContacted = nodeA.name == "REDBLOCK" || nodeB.name == "REDBLOCK" 
    let yellowContacted = nodeA.name == "YELLOWBLOCK" || nodeB.name == "YELLOWBLOCK" 
    let greenContacted = nodeA.name == "GREENBLOCK" || nodeB.name == "GREENBLOCK" 

    var removableNodeName: String? 

    if blueContacted && yellowContacted { 
     removableNodeName = "YELLOWBLOCK" 
    } else if redContacted && greenContacted { 
     removableNodeName = "GREENBLOCK" 
    } else if yellowContacted && blueContacted { 
     removableNodeName = "BLUEBLOCK" 
    } else if greenContacted && redContacted { 
     removableNodeName = "REDBLOCK" 
    } 

    if let nodeName = removableNodeName { 
     score += 1 
     scoreLabel?.text = "\(score)" 
     if nodeA.name == nodeName { 
      nodeA.run(SKAction.move(to: CGPoint(x: 0 , y: 360), duration: 0.3)) 
      nodeA.run(SKAction.fadeOut(withDuration: 0.3)) 
     } else { 
      nodeB.run(SKAction.move(to: CGPoint(x: 0 , y: 360), duration: 0.3)) 
      nodeB.run(SKAction.fadeOut(withDuration: 0.3)) 
     } 
    } else { // Any other contact means game over 
     nodeA.removeFromParent() 
     nodeB.removeFromParent() 
     score = 0 
     scoreLabel?.text = "\(score)" 
     gameOver() 
    } 
} 

编辑：根据下面的讨论添加了一些警卫来检查physicsBody上节点的存在。