存储没有映射表的JSP HashMap？

Question

它可能有两个类Template和TemplateItem，映射到两个数据库表template和template_item，它们使用Map<String, TemplateItem>？如果是这样，可以使用注释完成？

以下结果在三个表中，即添加一个不必要的映射表。

@Entity 
@Table(name = "template") 
public class Template { 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    @Column(name="id") 
    private long id = 0; 

    @Column(name="name") 
    private String name = ""; 

    // Left side of map maps to name field of the item on the right side of the map. 
    @OneToMany(cascade=CascadeType.ALL, fetch=FetchType.LAZY) 
    @MapKey(name = "name") 
    private Map<String, TemplateItem> items = new HashMap<String, TemplateItem>(); 

} 


@Entity 
@Table(name = "template_item") 
public class TemplateItem { 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    @Column(name="id") 
    private long id = 0; 

    // The name field is the unique key for the Template.items Map 
    @Column(name="name") 
    private String name = ""; 

    @ManyToOne(cascade=CascadeType.ALL, fetch=FetchType.LAZY) 
    private Template template; 

    @Column(name="content") 
    private String content = ""; 

} 

在MySQL中，我们得到了三个表，映射表包含两列复制出TemplateItem表：

+-------------+--------------+------+-----+---------+----------------+ 
| Field  | Type   | Null | Key | Default | Extra   | 
+-------------+--------------+------+-----+---------+----------------+ 
| id   | bigint(20) | NO | PRI | NULL | auto_increment | 
| name  | varchar(100) | NO | UNI | NULL |    | 
+-------------+--------------+------+-----+---------+----------------+ 

+-------------+--------------+------+-----+---------+----------------+ 
| Field  | Type   | Null | Key | Default | Extra   | 
+-------------+--------------+------+-----+---------+----------------+ 
| id   | bigint(20) | NO | PRI | NULL | auto_increment | 
| content  | longtext  | NO |  | NULL |    | 
| name  | varchar(120) | NO |  | NULL |    | 
| template_id | bigint(20) | YES | MUL | NULL |    | 
+-------------+--------------+------+-----+---------+----------------+ 

+----------------+------------+------+-----+---------+-------+ 
| Field   | Type  | Null | Key | Default | Extra | 
+----------------+------------+------+-----+---------+-------+ 
| at_template_id | bigint(20) | NO | PRI | NULL |  | 
| items_id  | bigint(20) | NO | PRI | NULL |  | 
+----------------+------------+------+-----+---------+-------+ 

Answer 1

标准JPA使用连接表的单向的OneToMany。通过指定拥有方来使关联双向，并且您不应该获得连接表：

@Entity 
@Table(name = "template") 
public class Template { 
    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    @Column(name="id") 
    private long id = 0; 

    @Column(name="name") 
    private String name = ""; 

    // Left side of map maps to name field of the item on the right side of the map 
    @OneToMany(cascade=CascadeType.ALL, fetch=FetchType.LAZY, mappedBy="template") 
    @MapKey(name = "name") 
    private Map items = new HashMap(); 
    ... 
}