一个查询获得一个月中每天的总＃条记录

Question

场景：

我有一个注册表，并有一个日期时间列。

我想在显示当前月份的每日注册数的网页上显示条形图。

我该如何做一个查询？即返回每天（当月）字段的结果集，当天的注册总数为

Answer 1

select day(Date), count(*) 
from table 
where month(Date) = month(NOW()) and year(Date) = year(NOW()) 
group by day(Date) 

“where”子句选择当前月份。您可以使用count(whatever)或count(distinct whatever)代替count(*) ......

Answer 2

事情是这样的伪代码：

SELECT Day, COUNT(*) 
FROM XXX_Users 
GROUP BY "date extracted from datetime" as Day 

要提取的日期时间，你可以使用DATE函数日期：

SELECT Day, COUNT(*) 
FROM XXX_Users 
GROUP BY DATE(created) as Day 

或者你可以创建一个存储过程来包含所有的逻辑