Sql查询从列转换为行

Question

我有很大的表151列 - 每列表示一个商店（150商店* 1列）加上一个日期列。

Date   Store001  Store002  Store003  Store004 ................... Store150 
---------------------------------------------------------------------------------------------------  
01/01/14  12560   8546   7468   10154      16845 

31/10/14  13978   7584   8456   13458      25458 

我需要的结果如下：

Date   Store#  Amount 
----------------------------------- 
01/01/14  Store001  12560 
01/01/14  Store002  8546 
01/01/14  Store003  7468 
01/01/14  Store004  10154 
etc., 

Answer 1

Create table yourtable([Date] date,Store001 int ,Store002 int) 
insert into yourtable ([Date],Store001,Store002) 
values 
(GETDATE(),1243,546), 
(GETDATE(),4545,798), 
(GETDATE(),5687,456), 
(GETDATE(),0756,685) 

简单查询

;WITH CTE 
AS 
    (
    SELECT * FROM (
    SELECT [Date],Store001,Store002 FROM yourtable) T 
    UNPIVOT (Value FOR N IN (Store001,Store002))P 
) 
SELECT [Date],N as Store#,SUM(Value) as Amount 
FROM CTE 
GROUP BY [Date],N 

动态SQL

declare @cols nvarchar(max) 
select @cols = coalesce(@cols+N',', N'') + quotename(c.name) from syscolumns c 
inner join sysobjects o on c.id = o.id and o.xtype = 'u' 
where o.name = 'yourtable' and c.name not in ('Date') order by c.colid 
select @cols 
declare @query nvarchar(max) 

select @query = N' 
;WITH CTE 
AS 
    (
    SELECT * FROM (
    SELECT [Date], ' + @cols + ' 
FROM yourtable) T 
    UNPIVOT (Value FOR N IN (' + @cols + '))P 
) 
SELECT [Date],N as Store#,SUM(Value) as Amount 
FROM CTE 
GROUP BY [Date],N 
' 
print @query 
exec sp_executesql @query 

输出

Date   Store#  Amount 
2014-11-02 Store001 12231 
2014-11-02 Store002 2485