我是一个在zend中开发,并有一个相当大的mysql查询。查询工作正常,我得到我期望的列表。我正在使用Select-> Where ....来执行此操作。以下是查询。从一个大的MySQL查询(zend)计数行
SELECT DISTINCT `d`.* FROM `deliverable` AS `d` INNER JOIN `groups` AS `g1` ON d.id = g1.deliverable_id INNER JOIN `groupmembers` AS `gm1` ON g1.id = gm1.group_id LEFT JOIN `connection` AS `c` ON d.id = c.downstreamnode_id LEFT JOIN `deliverable` AS `d1` ON c.upstreamnode_id = d1.id INNER JOIN `deliverable` AS `d2` ON CASE WHEN d1.id IS NULL THEN d.id ELSE d1.id END = d2.id INNER JOIN `groups` AS `g` ON d2.id = g.deliverable_id INNER JOIN `groupmembers` AS `gm` ON g.id = gm.group_id WHERE (g1.group_type = 100) AND (gm1.member_id = 1) AND (c.downstreamnode_id IS NULL OR d.restrict_access = 1) AND (g.group_type = 100 OR g.group_type = 110) AND (gm.member_id = 1) AND (d.deliverable_type = 110 OR d.deliverable_type = 100) GROUP BY CASE WHEN c.downstreamnode_id IS NULL THEN d.id ELSE c.downstreamnode_id END
唯一的问题是当我尝试计算mysql查询中的行时,我只得到1返回。下面是查询
SELECT DISTINCT count(*) AS `rowCount` FROM `deliverable` AS `d` INNER JOIN `groups` AS `g1` ON d.id = g1.deliverable_id INNER JOIN `groupmembers` AS `gm1` ON g1.id = gm1.group_id LEFT JOIN `connection` AS `c` ON d.id = c.downstreamnode_id LEFT JOIN `deliverable` AS `d1` ON c.upstreamnode_id = d1.id INNER JOIN `deliverable` AS `d2` ON CASE WHEN d1.id IS NULL THEN d.id ELSE d1.id END = d2.id INNER JOIN `groups` AS `g` ON d2.id = g.deliverable_id INNER JOIN `groupmembers` AS `gm` ON g.id = gm.group_id WHERE (g1.group_type = 100) AND (gm1.member_id = 1) AND (c.downstreamnode_id IS NULL OR d.restrict_access = 1) AND (g.group_type = 100 OR g.group_type = 110) AND (gm.member_id = 1) AND (d.deliverable_type = 110 OR d.deliverable_type = 100) GROUP BY CASE WHEN c.downstreamnode_id IS NULL THEN d.id ELSE c.downstreamnode_id END
我产生这种从使用相同的“选择”生成第一查询,但我重置的列和添加数。
$this->getAdapter()->setFetchMode(Zend_Db::FETCH_ASSOC);
$select
->reset(Zend_Db_Select::COLUMNS)
->columns(array('count('.$column.') as rowCount'));
$rowCount = $this->getAdapter()->fetchOne($select);
此方法适用罚款全部我的其他查询只有这一个我有麻烦。我怀疑它有些事情要做,因为我在第一个查询中得到了正确的行,这很奇怪。有任何想法吗。谢谢。
以下FYI是我成功工作的两个查询。
SELECT DISTINCT `po`.* FROM `post` AS `po` INNER JOIN `postinfo` AS `p` ON po.postinfo_id = p.id WHERE (p.creator_id = 1) ORDER BY `p`.`date_created` DESC
SELECT DISTINCT count(*) AS `rowCount` FROM `post` AS `po` INNER JOIN `postinfo` AS `p` ON po.postinfo_id = p.id WHERE (p.creator_id = 1) ORDER BY `p`.`date_created` DESC
在这一个我有4行返回在第一个查询和'int 4'返回第二个。有谁知道为什么它不适用于大查询?
谢谢,但它没有奏效。只是为了确认下面的代码按预期工作。 SELECT DISTINCT count(*)AS'rowCount' FROM'post' AS'po' 即使是不同的地方,它是我发布的另一个查询,我遇到了麻烦。我甚至试图摆脱这些独特的一切,但没有运气仍然返回1.任何其他的想法?谢谢 – viciouskinid 2012-03-15 22:18:09
您提到的第二项查询工作可能不符合您的期望。 'SELECT DISTINCT count(*)'将计算所有行,而不仅仅是唯一的行,然后返回1行作为结果。然后'DISTINCT'会将其过滤为只有唯一的行,但由于只有一行被返回(计数),所以无法包含“DISTINCT”。如果您想计算不同的行,您必须将“DISTINCT”放置在“COUNT”内。 – Interrobang 2012-03-15 22:33:28