MySQL查询：SUM计数重复行

Question

我有一个查询可以为我们的客户生成损益表，但我在加入订单表时遇到问题，导致SUM乘以费用分录数量。

我有以下表格：

• user_report_categories， “URC”，这是类的标题对于谁报告
• user_report_expenses， “茜”，这是个人的开支，以 “adjusted_cost” 用户和一个“费用日期”。这些可能会或可能不会有与它们相关的订单，但在这种情况下，我们只关心与订单相关的费用。每个订单可能有多个开支，但每个开支/订单将始终处于不同的类别。
• 订单，“O”，它有一个“agreed_fee”，“平衡”，当然，一个“id”

报告需要用户选择的日期范围内具有每月一列，用单元格中的计算值。

查询原样如下：

SELECT 
SUBSTRING(MONTHNAME(STR_TO_DATE(m, '%m')), 1, 3) AS month, 
COUNT(o.id) AS "# of Orders", 
ROUND(SUM(o.agreed_fee) - SUM(o.balance), 2) AS "Total Income", 
ROUND(SUM(ure.adjusted_cost), 2) AS "Total Expenses", 
ROUND(SUM(o.agreed_fee) - SUM(o.balance) - SUM(ure.adjusted_cost), 2) AS "Profit & Loss", 
"" AS "", 
ROUND(SUM(ure.adjusted_cost)/COUNT(ure.id), 2) AS "% of Expenses per Order", 
ROUND((SUM(o.agreed_fee) - SUM(o.balance))/COUNT(ure.id), 2) AS "Average Fee per Order", 
ROUND(((SUM(o.agreed_fee) - SUM(o.balance))/COUNT(ure.id)) - (SUM(ure.adjusted_cost)/COUNT(ure.id)), 2) AS "Average P/L per Order" 

FROM ( 
    SELECT y, m FROM 
    (SELECT YEAR('2016-01-01') y) years, 
    (SELECT 1 m UNION ALL SELECT 2 UNION ALL SELECT 3) months 
) ym 

LEFT JOIN user_report_categories AS urc ON urc.user_id = 48 
LEFT JOIN user_report_entries AS ure ON ure.user_category_id = urc.id AND YEAR(ure.expense_date) = y AND MONTH(ure.expense_date) = m 
LEFT JOIN orders AS o ON o.id = ure.order_id 
WHERE urc.report_type = 'expense' AND urc.user_id = 48 AND ure.order_id IS NOT NULL 
GROUP BY y, m 

和结果：

month,# of Orders,Total Income,Total Expenses,Profit & Loss,,% of Expenses per Order,Average Fee per Order,Average P/L per Order 
Jan,387,36400.00,5921.17,30478.83,,15.30,94.06,78.76 
Feb,559,55327.50,8165.12,47162.38,,14.61,98.98,84.37 
Mar,736,74785.00,10261.07,64523.93,,13.94,101.61,87.67 

我确定通过将订单ID的组由该订单被乘以的支出数

GROUP BY y, m, o.id 

并查看每行有多个订单的新结果：

month,# of Orders,Total Income,Total Expenses,Profit & Loss,,% of Expenses per Order,Average Fee per Order,Average P/L per Order 
Jan,6,360.00,31.95,328.05,,5.33,60.00,54.68 
Jan,1,0.00,30.24,-30.24,,30.24,0.00,-30.24 
Jan,6,1200.00,141.74,1058.26,,23.62,200.00,176.38 
Jan,6,540.00,160.97,379.03,,26.83,90.00,63.17 
Jan,6,540.00,98.77,441.23,,16.46,90.00,73.54 
Jan,8,720.00,167.44,552.56,,20.93,90.00,69.07 
... etc ... 

或者，当我从组通过删除o.id，而是改变订单行＃数不同：

COUNT(DISTINCT o.id) AS "# of Orders", 

我得到正确的价值观为订单＃，但当然由于重复，SUM顺序表值的其他值仍然不正确。

month,# of Orders,Total Income,Total Expenses,Profit & Loss,,% of Expenses per Order,Average Fee per Order,Average P/L per Order 
Jan,71,36400.00,5921.17,30478.83,,15.30,94.06,78.76 
Feb,105,55327.50,8165.12,47162.38,,14.61,98.98,84.37 
Mar,146,74785.00,10261.07,64523.93,,13.94,101.61,87.67 

我不知道如果我即使考虑一个好方法这一点，但在一个查询中这样做产生是一个巨大的优势，对我来说，所以我试图拼凑一起。我怎样才能得到它在不同的订单ID的SUM订单表值，否则更正查询以正确计算？谢谢！

---

回答

@Sal踢我了，我有结束最后的查询如下。我认为它也涵盖了评论中出现的所有问题。

SELECT 
SUBSTRING(MONTHNAME(STR_TO_DATE(m, '%m')), 1, 3) AS month, 
orders AS "# of Orders", 
round(total_income,2) AS "Total Income", 
round(total_expenses,2) AS "Total Expenses", 
round(total_income-total_expenses,2) AS "Profit & Loss", 
"" AS "", 
round(total_expenses/orders,2) AS "% of Expenses per Order", 
round(total_income/orders,2) AS "Average Fee per Order", 
round((total_income/orders)-(total_expenses/orders), 2) AS "Average P/L per Order" 

     FROM ( 
      SELECT m, 
      (SELECT count(o.id) 
       FROM orders o 
       WHERE year(o.datetime) = ym.y 
       AND month(o.datetime) = ym.m AND o.user_id = 48 
       AND o.cancelled = 0 
      ) AS orders, 
      (SELECT IFNULL(sum(o.agreed_fee - o.balance), 0) 
       FROM orders AS o 
       WHERE year(o.datetime) = ym.y 
       AND month(o.datetime) = ym.m 
       AND o.user_id = 48 
       AND o.cancelled = 0 
      ) AS total_income, 
      (SELECT IFNULL(sum(ure.adjusted_cost),0) 
       FROM user_report_entries AS ure 
       INNER JOIN user_report_categories AS urc ON urc.id = ure.user_category_id 
        WHERE year(ure.expense_date) = ym.y 
       AND month(ure.expense_date) = ym.m 
       AND urc.user_id = 48 AND urc.id NOT IN (6287)) AS total_expenses 
      FROM (SELECT 2017 y, 1 m UNION SELECT 2017, 2 UNION SELECT 2017, 3 
      ) ym 

      GROUP BY y, m 
     ) t 

Answer 1

我希望对您有所帮助：

SELECT substring(monthname(str_to_date(m,'%m'), 1, 3) month 
    , orders "# of Orders" 
    , round(total_income,2) "Total Income" 
    , round(total_expenses,2) "Total Expenses" 
    , round(total_income-total_expenses,2) "Profit & Loss" 
    , round(total_expenses/orders,2) "% of Expenses per Order" 
    , round(total_income/orders,2) "Average Fee per Order" 
    , round((total_income/orders)-(total_expenses/orders), 2) "Average P/L per Order" 
    FROM (SELECT m 
       , (SELECT count(distinct ure.order_id) 
        FROM user_report_entries ure 
        WHERE year(ure.expense_date) = ym.y 
         AND month(ure.expense_date) = ym.m 
       ) orders 
       , (SELECT sum(o.agreed_fee - o.balance) 
        FROM user_report_entries ure 
         INNER JOIN orders o 
         ON o.id = ure.order_id    
        WHERE year(ure.expense_date) = ym.y 
         AND month(ure.expense_date) = ym.m 
       ) total_income 
       , sum(ure.adjusted_cost) total_expenses 
      FROM (SELECT 2016 y, 1 m 
        UNION 
        SELECT 2016, 2 
        UNION 
        SELECT 2016, 3 
       ) ym 
      LEFT JOIN user_report_entries ure 
       ON year(ure.expense_date) = ym.y 
       AND month(ure.expense_date) = ym.m 
      LEFT JOIN user_report_categories urc 
       ON urc.id = ure.user_category_id 
      WHERE urc.user_id = 48 
      AND urc.report_type = 'expense' 
      GROUP BY y, m 
     ) t