我想计算一些非常简单的东西,但我找不到解决方案。我想切入一些数字,但我想保存垃圾箱。如何在不同的容器中切割一个数字并用新的容器扩展数据框?
bin.size = 100
df = data.frame(x =c(300,400),
y = c("sca1","sca2"))
cut(df$x, seq(0, 400, bin.size),
include.lowest = TRUE)
给我
[1] (200,300] (300,400]
Levels: [0,100] (100,200] (200,300] (300,400]
但我想是这样的:
bin y
1 (0,100] sca1
2 (100,200] sca1
3 (200,300] sca1
4 (0,100] sca2
5 (100,200] sca2
6 (200,300] sca2
7 (300,400] sca2
我想这样做,因为我想计算出在垃圾箱输入值的数量100.例如:
df2 = data.frame(snp = c(1,2,10,100,1,2,14,16,399),
sca = c("sca1","sca1","sca1","sca1","sca2","sca2","sca2","sca2","sca2"))
df2
snp sca
1 1 sca1
2 2 sca1
3 10 sca1
4 100 sca1
5 1 sca2
6 2 sca2
7 14 sca2
8 16 sca2
9 399 sca2
snp可能是向量sca1中的位置。
的最终目标是要获得这样的:
bin y num
1 (0,100] sca1 4
2 (100,200] sca1 0
3 (200,300] sca1 0
4 (0,100] sca2 4
5 (100,200] sca2 0
6 (200,300] sca2 0
7 (300,400] sca2 1
我能做的最好的是这样的:
df2$cat = cut(df2$snp, seq(0, 400, bin.size),
include.lowest = TRUE)
df2
snp sca cat
1 1 sca1 [0,100]
2 2 sca1 [0,100]
3 10 sca1 [0,100]
4 100 sca1 [0,100]
5 1 sca2 [0,100]
6 2 sca2 [0,100]
7 14 sca2 [0,100]
8 16 sca2 [0,100]
9 399 sca2 (300,400]
或者这样:
table(df2$cat,df2$sca)
sca1 sca2
[0,100] 4 4
(100,200] 0 0
(200,300] 0 0
(300,400] 0 1
但随着问题这最后一次尝试是(300,400]
对sca1
没有意义,因为它确实不存在。它应该是NA
或者不显示。如何解决这个问题?
为什么不'(300,400]'意义鉴于输入'df2' ,'(100,200]'和'(200,300]'不应该出现在'sca1'? – thelatemail
事实上,0和NA在我的分析中并不相同,所以我需要改变它。预计,我没有使用这些数据,这只是一个可重复的例子。 –