合并facebook文件和图像的配置文件

Question

我试图biuld Facebook的应用程序，我将用户配置文件图像与背景图像和用户的名称合并。这张图片是对成功回答测验的人的回报。

这是从用户正在提交有答案后direceted页的初步认识代码：

 if ($totalCorrect == 10) { 
     echo "Congrats!"; 

      echo "<div id='results'>$totalCorrect/10 correct</div>"; 


     echo '<img src="image.php">'; 

     ?> 

这是image.php代码

<?php 
// Create image instances 




$im = imagecreatefromjpeg('xxx.jpg'); 



$black = ImageColorAllocate($im, 0, 0, 0); 




//The canvas's (0,0) position is the upper left corner 
//So this is how far down and to the right the text should start 
$start_x = 200; 
$start_y = 20; 

$font = 'arial.ttf'; 


Imagettftext($im, 12, 0, $start_x, $start_y, $black, $font, 'text to write'); 

$url = "http://graph.facebook.com/".$user_profile. "/picture"; 


$dest = imagecreatefromjpeg($url); 

// Copy and merge 
imagecopymerge($im, $dest, 10, 10, 0, 0, 180, 180, 100); 


//Creates the jpeg image and sends it to the browser 
//100 is the jpeg quality percentage 

// Output and free from memory 
header('Content-Type: image/jpg'); 
imagejpeg($im); 



imagedestroy($dest); 
imagedestroy($src); 
?> 

如果我交换$ url到代码工作的静态图像，但不是当我尝试获取用户的配置文件时。有什么建议么？感谢您的支持！

Answer 1

创建新的PHP文件名a.php只会和存储以下

$headers = get_headers('https://graph.facebook.com/".$user[id]."/picture',1); 
$url = $headers['Location']; 

上的原始文件，调用a.php只会文件象下面这样：

require_once 'a.php'; 

$dst = imagecreatefromjpeg($url); 
imagecopymerge($im, $dest, 10, 10, 0, 0, 180, 180, 100); 

希望它能帮助！