我已阅读了许多代码,但没有发生任何事情来解决问题。首先是代码:序列化/删除对象/结构阵列
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using System.Runtime.Serialization.Formatters.Binary;
namespace Serialization
{
class Program
{
static void Main(string[] args)
{
using (MoveSaver objSaver = new MoveSaver(@"C:\1.bin"))
{
MoveAndTime mv1, mv2;
mv1.MoveStruc = "1";
mv1.timeHLd = DateTime.Now;
objSaver.SaveToFile(mv1);
mv2.MoveStruc = "2";
mv2.timeHLd = DateTime.Now;
objSaver.SaveToFile(mv2);
}
using (MoveSaver svrObj = new MoveSaver())
{
MoveAndTime[] MVTobjs = svrObj.DeSerializeObject(@"C:\1.bin");
foreach (MoveAndTime item in MVTobjs)
{
//Do Something
}
}
}
}
public class MoveSaver:IDisposable
{
public void Dispose()
{
if (fs != null)
{
fs.Close();
}
}
FileStream fs;
StreamWriter sw;
public string filename { get; set; }
public MoveSaver(string FileName)
{
this.filename = FileName;
fs = new FileStream(filename, FileMode.OpenOrCreate, FileAccess.ReadWrite);
}
public MoveSaver()
{
}
~MoveSaver()
{
if (fs != null)
{
fs.Close();
}
}
public MoveAndTime[] DeSerializeObject(string filename)
{
MoveAndTime[] objectToSerialize;
Stream stream = File.Open(filename, FileMode.Open);
BinaryFormatter bFormatter = new BinaryFormatter();
objectToSerialize = (MoveAndTime[])bFormatter.Deserialize(stream);
stream.Close();
return objectToSerialize;
}
public bool SaveToFile(MoveAndTime moveTime)
{
try
{
BinaryFormatter bformatter = new BinaryFormatter();
bformatter.Serialize(fs, moveTime);
return true;
}
catch (Exception)
{
return false;
}
}
}
[Serializable]
public struct MoveAndTime
{
public string MoveStruc;
public DateTime timeHLd;
}
}
该代码模仿需要保存用户在程序中的所有操作。稍后会在该程序中显示(比如说你打牌或者想要检查:D发生了什么)。问题是当DeSerializeObject函数被称为线objectToSerialize = (MoveAndTime[])bFormatter.Deserialize(stream);
抛出异常(绝对在运行时),从一个单一的对象阵列的转换无效:
无法转换类型 “Serialization.MoveAndTime”的对象键入 'Serialization.MoveAndTime []'。
任何想法?任何改进或方法的全面改变表示赞赏。
你不应该有一个终结 – SLaks