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红宝石解密加密字符串我使用的ActiveSupport :: MessageEncryptor如下加密在Ruby中的字符串:不能在斯卡拉
salt = SecureRandom.random_bytes(64)
// => "s\x90L\xB8\xEF\x8BBp\xB6\xF5A\x95\xA8]+\x94\xF3\xA7\x9A\x84+jC\xBF\xB0\x15\xEF*\x8C\xDD.\xE5\xC7Y\xCE\xE1\xAA\xA4I/%.\x9E\x14\xC1\xA8\x9E\x122\xE0\x19.\x19\xD8\xB6\xE8\x83\xE1\xFE\x16\xB5\x11N\x18"
key = ActiveSupport::KeyGenerator.new('password').generate_key(salt)
// => "\x12\xBD1\xA0Q\xBF)\\\x89\xDF\x95\xD0\f\x03\x17P'\x87\xAD\x92b\xB5%\xC7X\x01\x9Ar\xCB\xC9\x1A\x10'\xC4\x95w\xBF\xED]\x17\xEB\x9F#\xC6\xEE8S\xE1^\x18\xE2^\x85Z\rJ\x9A\xEE\xA5\xEC|\xA2\xA9\x8E"
crypt = ActiveSupport::MessageEncryptor.new(key)
encrypted_username = crypt.encrypt_and_sign("daniel")
// => "N0dHcFM3MnQrcW1HUk9UTGwxeUJsZmlCNzcwUGhrdUdtbE9YWnUxamZFST0tLUVUcUlIU2k1ZHIvTmlDRUgzM2FsS0E9PQ==--1ede80eb2b498ddf5133f8f3a45a82db2476c740"
然后在斯卡拉我试图解密像这样:
var encrypted_str = "N0dHcFM3MnQrcW1HUk9UTGwxeUJsZmlCNzcwUGhrdUdtbE9YWnUxamZFST0tLUVUcUlIU2k1ZHIvTmlDRUgzM2FsS0E9PQ==--1ede80eb2b498ddf5133f8f3a45a82db2476c740"
val parts = encrypted_str.split("--");
val encryptedData = Base64.decodeBase64(parts(0))
val iv = Base64.decodeBase64(parts(1))
val cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.DECRYPT_MODE, aesKey, new IvParameterSpec(iv.take(16)));
val result = cipher.doFinal(encryptedData);
println(new String(result, "UTF-8"))
但我碰上此错误:
javax.crypto.IllegalBlockSizeException:带衬垫的密
解密时输入长度必须为16的倍数
尝试用Scala加密它,看看你会得到相同的结果。 xD –
这是行不通的我认为.... ruby使用一个随机的iv被追加到加密的字符串 – Daniel