正如上面@Devs,你必须通过一些贴图参数(地名或坐标),以google.html您页。我修改了招呼页面:
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>
<body>
<address>
Sector 75-Noid...
</address>
<a href="google.html?q=France"><button type="button">view on map</button></a>
<address>Delhi</address>
<a href="google.html?q=Delhi"><button type="button">view on map</button></a>
</body>
</html>
正如你所看到的,google.html您的联系现在有“Q”的查询字符串参数,这将在google.html您页面中使用:
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<script src="http://jashkenas.github.com/coffee-script/extras/coffee-script.js"></script>
<meta charset=utf-8 />
<title>Welcome to JS Bin</title>
<meta name="viewport" content="width=device-width">
<link href='http://fonts.googleapis.com/css?family=Doppio+One' rel='stylesheet' type='text/css'>
<script type="text/javascript">
$(document).ready(function() {
$("address").each(function() {
var embed ="<iframe width='425' height='350' frameborder='0' scrolling='no' marginheight='0' marginwidth='0' src='https://maps.google.com/maps?&q="+ encodeURIComponent(getParameterByName('q')) +"&output=embed'></iframe>";
$(this).html(embed);
});
function getParameterByName(name, url) {
if (!url) {
url = window.location.href;
}
name = name.replace(/[\[\]]/g, "\\$&");
var regex = new RegExp("[?&]" + name + "(=([^&#]*)|&|#|$)"),
results = regex.exec(url);
if (!results) return null;
if (!results[2]) return '';
return decodeURIComponent(results[2].replace(/\+/g, " "));
}
});
</script>
</head>
<body>
<address>Australia</address>
</body>
</html>
你可以尝试在工作演示here
你从来没有通过任何地图参数或坐标来google.html您 –
那么,如何解决这个问题请告诉我 – neha
的链接是死在了这个问题,对于依靠任何问题的危险在外部链接上。这确实意味着它需要关闭。请尝试尽可能保持您的问题独立,以限制所需的关闭和删除数量。 – halfer