尝试向sqlite数据库表中插入值时应用程序崩溃

我创建了一个包含少量表的数据库。当我调用Database.java时，数据库被创建（应用程序不崩溃）。尝试向sqlite数据库表中插入值时应用程序崩溃

当我尝试插入登录表时，应用程序崩溃。我不知道下一步该怎么做。我认为问题出在表插入代码。

表创建代码（Database.java）

public static final String db="shg.db"; 
public static final int version=1; 

public Database(Context context) { 
    super(context, db, null, version); 
} 

@Override 
public void onCreate(SQLiteDatabase db) { 
    db.execSQL("create table if not exists login(id integer primary key autoincrement,log_name text,log_pass text)"); 
    db.execSQL("create table if not exists members(foreign key (id) REFERENCES login(id),mem_name text,mem_dob date,mem_address text,mem_phno text)"); 
    db.execSQL("create table if not exists committee(foreign key (id) REFERENCES login(id),committee_id int autoincrement,committee_date date)"); 
    db.execSQL("create table if not exists status(foreign key (id) REFERENCES login(id),loan_count int,thrift_complete int)"); 
    db.execSQL("create table if not exists attendance(foreign key (committee_id) REFERENCES login(committee_id),foreign key (id) REFERENCES login(id))"); 
    db.execSQL("create table if not exists loan(loan_id int,foreign key (committee_id) REFERENCES login(committee_id),foreign key (id) REFERENCES login(id),amount numeric)"); 
    db.execSQL("create table if not exists loanrepayment(foreign key (id) REFERENCES login(id),foreign key (loan_id) REFERENCES login(loan_id),foreign key(committee_id) REFERENCES login(committee_id),amount numeric,interest numeric)"); 
    db.execSQL("create table if not exists thrift(foreign key (committee_id) REFERENCES login(committee_id),foreign key (id) REFERENCES login(id),amount numeric)"); 
    db.execSQL("create table if not exists fine(foreign key (committee_id) REFERENCES login(committee_id),foreign key (id) REFERENCES login(id),amount numeric,reason text)"); 
} 

@Override 
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) { 
} 

public boolean insertlogin(String name,String pass) { 
    SQLiteDatabase db = this.getWritableDatabase(); 
    ContentValues cv = new ContentValues(); 
    cv.put("log_name",name); 
    cv.put("log_pass",pass); 
    db.insert("login",null,cv); 
    return true; 
} 
public Cursor getlogin(String uname,String upass) { 
    Cursor c; 
    String qry="select * from login where log_name ="+uname+" and log_pass =" +upass+";"; 
    SQLiteDatabase db = this.getReadableDatabase(); 
    String[]col_name={"log_name","log_pass"}; 
    String whereClause = "log_name = ? OR log_pass = ?"; 
    String[] whereArgs = new String[] {uname, upass}; 
    c=db.query("login",col_name,whereClause,whereArgs,null,null,null); 
    return c; 
}

数据库插入代码（MainActivity.java）

db=new Database(this); 
Boolean status=db.insertlogin("a","b"); 
Toast.makeText(MainActivity.this, ""+status, Toast.LENGTH_SHORT).show();

不知何故，我已设法我的设备I期间已经使用上运行的应用程序开发项目的阶段（没有崩溃）。当我尝试在新设备上运行项目时，应用程序崩溃。

E/SQLiteLog: (1) near "foreign": syntax error 
E/AndroidRuntime: FATAL EXCEPTION: main 
Process: droid.dev.shg.shg, PID: 29705 
java.lang.RuntimeException: Unable to start activity ComponentInfo{droid.dev.shg.shg/droid.dev.shg.shg.MainActivity}: android.database.sqlite.SQLiteException: near "foreign": syntax error (code 1): , while compiling: create table if not exists members(foreign key (id) REFERENCES login(id),mem_name text,mem_dob date,mem_address text,mem_phno text) 
    at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2584) 
    at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2666) 
    at android.app.ActivityThread.handleRelaunchActivity(ActivityThread.java:4336) 
    at android.app.ActivityThread.-wrap15(ActivityThread.java) 
    at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1499) 
    at android.os.Handler.dispatchMessage(Handler.java:111) 
    at android.os.Looper.loop(Looper.java:207) 
    at android.app.ActivityThread.main(ActivityThread.java:5769) 
    at java.lang.reflect.Method.invoke(Native Method) 
    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:789) 
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:679) 
Caused by: android.database.sqlite.SQLiteException: near "foreign": syntax error (code 1): , while compiling: create table if not exists members(foreign key (id) REFERENCES login(id),mem_name text,mem_dob date,mem_address text,mem_phno text) 
    at android.database.sqlite.SQLiteConnection.nativePrepareStatement(Native Method) 
    at android.database.sqlite.SQLiteConnection.acquirePreparedStatement(SQLiteConnection.java:896) 
    at android.database.sqlite.SQLiteConnection.prepare(SQLiteConnection.java:507) 
    at android.database.sqlite.SQLiteSession.prepare(SQLiteSession.java:588) 
    at android.database.sqlite.SQLiteProgram.<init>(SQLiteProgram.java:58) 
    at android.database.sqlite.SQLiteStatement.<init>(SQLiteStatement.java:31) 
    at android.database.sqlite.SQLiteDatabase.executeSql(SQLiteDatabase.java:1704) 
    at android.database.sqlite.SQLiteDatabase.execSQL(SQLiteDatabase.java:1635) 
    at droid.dev.shg.shg.Database.onCreate(Database.java:22) 
    at android.database.sqlite.SQLiteOpenHelper.getDatabaseLocked(SQLiteOpenHelper.java:251) 
    at android.database.sqlite.SQLiteOpenHelper.getWritableDatabase(SQLiteOpenHelper.java:163) 
    at droid.dev.shg.shg.Database.insertlogin(Database.java:39) 
    at droid.dev.shg.shg.MainActivity$override.onCreate(MainActivity.java:30) 
    at droid.dev.shg.shg.MainActivity$override.access$dispatch(MainActivity.java) 
    at droid.dev.shg.shg.MainActivity.onCreate(MainActivity.java:0) 
    at android.app.Activity.performCreate(Activity.java:6583) 
    at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1114) 
    at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2531) 
    at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2666)  
    at android.app.ActivityThread.handleRelaunchActivity(ActivityThread.java:4336)  
    at android.app.ActivityThread.-wrap15(ActivityThread.java)  
    at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1499)  
    at android.os.Handler.dispatchMessage(Handler.java:111)  
    at android.os.Looper.loop(Looper.java:207)  
    at android.app.ActivityThread.main(ActivityThread.java:5769)  
    at java.lang.reflect.Method.invoke(Native Method)  
    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:789)  
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:679)

来源

2016-07-31 Android.Doubts

这是数据库设计好????? –

因为你的SQL查询是错误的。例如'...成员（外键（id）REFERENCES登录（id）'。我建议用SQL工具对数据库进行操作并将其与应用程序一起部署为资产 –

如何纠正它。？请向我展示一个示例 –

您的“外键”需要以正常方式声明，然后分配为外键。例如：

create table members(id INTEGER, mem_name TEXT, FOREIGN KEY(id) REFERENCE login(id))

来源

2016-07-31 14:53:26 Drgabble

谢谢!!它真的帮助 –

高兴地帮助:)请点击接受，如果你认为它的正确答案 – Drgabble

你必须改变你的SQL查询到类似下面：

create table if not exists members(id integer, mem_name text,mem_dob date,mem_address text,mem_phno text, FOREIGN KEY (id) REFERENCES login(id))

FOREIGN KEY必须定义退出现场。

来源

2016-07-31 14:52:14 SadeghAlavizadeh

谢谢!!它真的帮助 –

所以请接受这个答案 – SadeghAlavizadeh

尝试向sqlite数据库表中插入值时应用程序崩溃

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