我setOnCheckedChangeListener
实现我checkbox
,而不会触发onCheckChanged
变化选择框的值是否有一种方法,我可以叫
checkbox.setChecked(false);
而不触发onCheckedChanged
我setOnCheckedChangeListener
实现我checkbox
,而不会触发onCheckChanged
变化选择框的值是否有一种方法,我可以叫
checkbox.setChecked(false);
而不触发onCheckedChanged
不,你不能这样做。 onCheckedChanged
方法直接从setChecked
调用。你可以做的是:
mCheck.setOnCheckedChangeListener (null);
mCheck.setChecked (false);
mCheck.setOnCheckedChangeListener (mListener);
见source of CheckBox,和setChecked
实施:
public void setChecked(boolean checked) {
if (mChecked != checked) {
mChecked = checked;
refreshDrawableState();
// Avoid infinite recursions if setChecked() is called from a listener
if (mBroadcasting) {
return;
}
mBroadcasting = true;
if (mOnCheckedChangeListener != null) {
mOnCheckedChangeListener.onCheckedChanged(this, mChecked);
}
if (mOnCheckedChangeWidgetListener != null) {
mOnCheckedChangeWidgetListener.onCheckedChanged(this, mChecked);
}
mBroadcasting = false;
}
}
我猜使用反射是唯一的出路。事情是这样的:
CheckBox cb = (CheckBox) findViewById(R.id.checkBox1);
try {
Field field = CompoundButton.class.getDeclaredField("mChecked");
field.setAccessible(true);
field.set(cb, cb.isChecked());
cb.refreshDrawableState();
cb.invalidate();
} catch (Exception e) {
e.printStackTrace();
}
另一种可能的方式实现这一目标是通过使用自定义复选框:
public class CheckBox extends AppCompatCheckBox {
private OnCheckedChangeListener mListener;
public CheckBox(final Context context) {
super(context);
}
public CheckBox(final Context context, final AttributeSet attrs) {
super(context, attrs);
}
public CheckBox(final Context context, final AttributeSet attrs, final int defStyleAttr) {
super(context, attrs, defStyleAttr);
}
@Override
public void setOnCheckedChangeListener(final OnCheckedChangeListener listener) {
mListener = listener;
super.setOnCheckedChangeListener(listener);
}
public void setChecked(final boolean checked, final boolean alsoNotify) {
if (!alsoNotify) {
super.setOnCheckedChangeListener(null);
super.setChecked(checked);
super.setOnCheckedChangeListener(mListener);
return;
}
super.setChecked(checked);
}
public void toggle(boolean alsoNotify) {
if (!alsoNotify) {
super.setOnCheckedChangeListener(null);
super.toggle();
super.setOnCheckedChangeListener(mListener);
}
super.toggle();
}
}
示例用法:
checkBox.setChecked(true,false);
您可以使用此SafeCheckBox类为您的复选框:
public class SafeCheckBox extends AppCompatCheckBox implements CompoundButton.OnCheckedChangeListener {
private OnSafeCheckedListener onSafeCheckedListener;
private int mIgnoreListener = CALL_LISTENER;
public static final int IGNORE = 0;
public static final int CALL_LISTENER = 1;
@Retention(RetentionPolicy.SOURCE)
@IntDef({IGNORE, CALL_LISTENER})
public @interface ListenerMode {
}
public SafeCheckBox(Context context) {
super(context);
init(context);
}
public SafeCheckBox(Context context, AttributeSet attrs) {
super(context, attrs);
init(context);
}
public SafeCheckBox(Context context, AttributeSet attrs, int defStyleAttr) {
super(context, attrs, defStyleAttr);
init(context);
}
/**
* @param checkState change state of the checkbox to
* @param mIgnoreListener true to ignore the listener else listener will be notified
*/
public void setSafeCheck(boolean checkState, @ListenerMode int mIgnoreListener) {
if (isChecked() == checkState) return; //already in the same state no need to fire listener.
if (onSafeCheckedListener != null) { // this to avoid a bug if the user listens for the event after using this method and in that case he will miss first check
this.mIgnoreListener = mIgnoreListener;
} else {
this.mIgnoreListener = CALL_LISTENER;
}
setChecked(checkState);
}
private void init(Context context) {
setOnCheckedChangeListener(this);
}
public OnSafeCheckedListener getOnSafeCheckedListener() {
return onSafeCheckedListener;
}
public void setOnSafeCheckedListener(OnSafeCheckedListener onSafeCheckedListener) {
this.onSafeCheckedListener = onSafeCheckedListener;
}
@Override
public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
if (onSafeCheckedListener != null)
onSafeCheckedListener.onAlwaysCalledListener(buttonView, isChecked);// this has to be called before onCheckedChange
if (onSafeCheckedListener != null && (mIgnoreListener == CALL_LISTENER)) {
onSafeCheckedListener.onCheckedChanged(buttonView, isChecked);
}
mIgnoreListener = CALL_LISTENER;
}
/**
* Listener that will be called when you want it to be called.
* On checked change listeners are called even when the setElementChecked is called from code. :(
*/
public interface OnSafeCheckedListener extends OnCheckedChangeListener {
void onAlwaysCalledListener(CompoundButton buttonView, boolean isChecked);
}
}
然后,你可以拨打电话: -
setSafeCheck(true,ListenerMode.IGNORE);// OnCheckedChange listener will not be notified
使用科特林的扩展与@Shade答案:
对于任何人,在这个过程中发现,一个简单的方法做,这是只使用上的复选框标签,然后检查其监听器标签(代码是在科特林):
checkBox.tag = false
checkBox.setOnCheckedChangeListener{ buttonView, isChecked ->
if(checkBox.tag != true) {
//Do some stuff
} else {
checkBox.tag = false
}
然后在访问刚刚设置的标签为true您设置的前
checkBox.tag = true
checkBox.isChecked = true
您还可以通过使用需要的一个关键,如果你担心可理解替代setTag方法映射标签的关键:当你想忽略值的变化来器isChecked真实。但是如果它的所有内容都包含在一个类中,那么一些注释字符串将足以解释发生了什么。
在检查单选按钮之前将null设置为changeListener。您可以在检查单选按钮后再次设置监听器。
radioGroup.setOnCheckedChangeListener(null);
radioGroup.check(R.id.radioButton);
radioGroup.setOnCheckedChangeListener(new
RadioGroup.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(RadioGroup radioGroup, @IdRes int i) {
}
});
我的解决方案用Java编写的基于@克里斯回答:
chkParent.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
if(buttonView.getTag() != null){
buttonView.setTag(null);
return;
}
if(isChecked){
chkChild.setTag(true);
chkChild.setChecked(false);
}
else{
chkParent.setChecked(true);
}
}
});
chkChild.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
if(buttonView.getTag() != null){
buttonView.setTag(null);
return;
}
if(isChecked){
chkParent.setTag(true);
chkParent.setChecked(false);
}
else{
chkChild.setChecked(true);
}
}
});
2复选框,并总是一个将被检查(之一必须首先检查虽然)。将标记设置为true可阻止onCheckedChanged侦听器。
我的理解,我认为这是最简单的
可能会有所帮助)
public class ProgrammableSwitchCompat extends SwitchCompat {
public boolean isCheckedProgrammatically = false;
public ProgrammableSwitchCompat(final Context context) {
super(context);
}
public ProgrammableSwitchCompat(final Context context, final AttributeSet attrs) {
super(context, attrs);
}
public ProgrammableSwitchCompat(final Context context, final AttributeSet attrs, final int defStyleAttr) {
super(context, attrs, defStyleAttr);
}
@Override
public void setChecked(boolean checked) {
isCheckedProgrammatically = false;
super.setChecked(checked);
}
public void setCheckedProgrammatically(boolean checked) {
isCheckedProgrammatically = true;
super.setChecked(checked);
}
}
使用它
@Override
public void onCheckedChanged(CompoundButton compoundButton, boolean on) {
if (((ProgrammableSwitchCompat) compoundButton).isCheckedProgrammatically) {
return;
}
//...
((ProgrammableSwitchCompat) compoundButton).setCheckedProgrammatically(true);
//...
((ProgrammableSwitchCompat) compoundButton).setCheckedProgrammatically(false);
//...
}
使用会引发setChecked(boolean)
功能
这是所有
这是我使用的简单解决方案:
定义自定义监听器:
class CompoundButtonListener implements CompoundButton.OnCheckedChangeListener {
boolean enabled = false;
@Override
public void onCheckedChanged(CompoundButton compoundButton, boolean checked) {
}
void enable() {
enabled = true;
}
void disable() {
enabled = false;
}
boolean isEnabled() {
return enabled;
}
}
初始化:
CompoundButtonListener checkBoxListener = new CompoundButtonListener() {
@Override
public void onCheckedChanged(CompoundButton compoundButton, boolean checked) {
if (isEnabled()) {
// Your code goes here
}
}
};
myCheckBox.setOnCheckedChangeListener(checkBoxListener);
用法:
checkBoxListener.disable();
// Some logic based on which you will modify CheckBox state
// Example: myCheckBox.setChecked(true)
checkBoxListener.enable();
你打算如何让'mListener'? 'Checkbox'没有getCheckChangeListener的吸气剂 – tir38 2014-07-08 19:56:18
好吧,不需要简单地downvote,因为你不明白解决方案。 'mListener'是由程序员创建的'OnCheckChangedListener'接口的一个实现。我的答案意味着程序员保留了对**自己的实现** - 'mListener'的引用。 – Shade 2014-07-09 08:20:52
如果您想重复使用setChecked()方法,更改侦听器会是低效的吗? – Ren 2016-04-22 22:01:20