传递价值与Servlet但servlet的不可

Question

我使用的IntelliJ IDEA 14创建一个Web应用程序中使用Servlet和JSP，但每当我试图通过值从JSP有误差

HTTP Status 404 - /Books/BookSaleAuctionServlet 

type Status report 

message /Books/BookSaleAuctionServlet 

description The requested resource is not available. 

Apache Tomcat/7.0.30 

Myfiles中有： 的index.jsp

<form method= "get" action="Books/BookSaleAuctionServlet"> 
    UserName : <input type="text" name="name" id="name"> 
    Address : <input type="text" name="address" id="address"> 
    Contact : <input type="tel" name="contactNo" id="contactNo"> 
    Email : <input type="email" name="email" id="email"> 
    Password : <input type="password" name="pass" id="pass"> 
    <input type="submit" name="save"> 

并且存在servlet作为BookSaleAuctionServletBooks封装内，并且它包含

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { 
     String name = request.getParameter("name"); 
     String address = request.getParameter("address"); 
     String contact = request.getParameter("contact"); 
     String email = request.getParameter("email"); 
     String pass = request.getParameter("pass"); 
     System.out.println("check 1"); 
     try { 
      Class.forName("com.mysql.jdbc.Driver"); 
     } 
     catch(ClassNotFoundException e) { 
      System.out.println("Class not found "+ e); 
     } 
     System.out.println("JDBC Class found"); 
     try { 
      Connection con = DriverManager.getConnection("jdbc:mysql://localhost/logins", "root", ""); 
      Statement stmt = con.createStatement(); 
      ResultSet rs = stmt.executeQuery 
        ("CREATE TABLE members (user_id int(11) NOT NULL AUTO_INCREMENT,\n" + 
          " username varchar(45) NOT NULL,\n" + 
          " password varchar(45) NOT NULL,\n" + 
          " contact varchar(45) NOT NULL,\n" + 
          " email varchar(45) NOT NULL,\n" + 
          " PRIMARY KEY (user_id)\n" + 
          "); ");  } 
     catch(SQLException e){ 
      System.out.println("SQL exception occured" + e); 
     } 
     System.out.print("done with databases"); 
    } 

和web.xml

<servlet> 
     <servlet-name>BookSaleAuctionServlet</servlet-name> 
     <servlet-class>Books.BookSaleAuctionServlet</servlet-class> 
    </servlet> 
    <servlet-mapping> 
     <servlet-name>BookSaleAuctionServlet</servlet-name> 
     <url-pattern>/bookSaleAuction</url-pattern> 
    </servlet-mapping> 

请帮助

Answer 1

变化 action="Books/BookSaleAuctionServlet" 到action="/bookSaleAuction"