2011-11-01 166 views
2

当我打电话给UpdateXML()时,我发现空节点正在转换为速记XML。有没有办法阻止UpdateXML()以这种方式运行,也许是一个标志或设置或替代XPath表达式来告诉它保留原始结构?Oracle UpdateXML()更改XML结构?

/* Example 1 */ 
SELECT UpdateXML(xmlData, '/TEST/VALUE/text()', 'hello') as "Example 1" 
    FROM (SELECT XMLType('<TEST><VALUE>hi</VALUE></TEST>') as xmlData 
      FROM DUAL); 

Example 1 
--------- 
<TEST><VALUE>hello</VALUE></TEST> 


/* Example 2 */ 
SELECT UpdateXML(xmlData, '/TEST/VALUE/text()', 'hello') as "Example 2" 
    FROM (SELECT XMLType('<TEST><VALUE></VALUE></TEST>') as xmlData 
      FROM DUAL); 

Example 2 
--------- 
<TEST><VALUE/></TEST> 

我想看到什么:

/* Desired Output, vs. Example 2 */ 
SELECT UpdateXML(xmlData, '/TEST/VALUE/text()', 'hello') as "Desired Output" 
    FROM (SELECT XMLType('<TEST><VALUE></VALUE></TEST>') as xmlData 
      FROM DUAL); 

Desired Output 
-------------- 
<TEST><VALUE></VALUE></TEST> 

回答

0

我想你可以用临时值替换空的文本,更新所有其他的文本,然后用替换临时值避免问题一个null。

我不明白的XPath,有可能是一个更好的方法来做到这一点,但是这似乎工作:

SELECT 
    --#3: Replace the temporary value with null, this keeps the start and end tag 
    UpdateXML(
     --#2: Replace everything but the temporary value 
     UpdateXML(
      --#1: Replace empty text with a temporary value 
      UpdateXML(xmlData, '/TEST/VALUE[not(text())]', '<VALUE>TEMPORARY VALUE</VALUE>') 
     ,'/TEST/VALUE[text()!="TEMPORARY VALUE"]/text()', 'hello') 
    ,'/TEST/VALUE[text()="TEMPORARY VALUE"]/text()', null) examle 
FROM (SELECT XMLType('<TEST><VALUE>hi</VALUE><VALUE>hola</VALUE><VALUE></VALUE></TEST>') as xmlData FROM DUAL); 
+0

有趣的方法,烨它的作品! – wweicker