将json转换为任意多维的数组？

Question

我想知道是否有人知道JS函数将json数组转换为javascript数组..

如何返回的json数组可能是多维的，或者它可能是单维...所以我想找到一个函数来构建javascript数组以迎合所有维度？

编辑：请不要建议一个库相关的功能，我不使用它们。

Answer 1

现代浏览器都已经这样做了：

JSON.parse('["foo", ["bar", ["foofoo", "barbar"]]]');

https://developer.mozilla.org/En/Using_native_JSON

但是你可能想要的东西，支持旧的浏览器： http://api.jquery.com/jQuery.parseJSON/

Answer 2

如果你的浏览器不有，我发现这个函数有一次（某处），它启用了JSON.stringify和JSON.parse：

var JSON; 
JSON||(JSON=function(){function v(x){return x<10?"0"+x:x}Date.prototype.toJSON=function(){return this.getUTCFullYear()+"-"+v(this.getUTCMonth()+1)+"-"+v(this.getUTCDate())+"T"+v(this.getUTCHours())+":"+v(this.getUTCMinutes())+":"+v(this.getUTCSeconds())+"Z"};String.prototype.toJSON=Number.prototype.toJSON=Boolean.prototype.toJSON=function(){return this.valueOf()};var i=/[\u0000\u00ad\u0600-\u0604\u070f\u17b4\u17b5\u200c-\u200f\u2028-\u202f\u2060-\u206f\ufeff\ufff0-\uffff]/g,m=/[\\\"\x00-\x1f\x7f-\x9f\u00ad\u0600-\u0604\u070f\u17b4\u17b5\u200c-\u200f\u2028-\u202f\u2060-\u206f\ufeff\ufff0-\uffff]/g,p, 
c,y={"\u0008":"\\b","\t":"\\t","\n":"\\n","\u000c":"\\f","\r":"\\r",'"':'\\"',"\\":"\\\\"},C;function I(x){m.lastIndex=0;return m.test(x)?'"'+x.replace(m,function(E){var u=y[E];if(typeof u==="string")return u;return"\\u"+("0000"+(+E.charCodeAt(0)).toString(16)).slice(-4)})+'"':'"'+x+'"'}function J(x,E){var u,A,s=p,t,w=E[x];if(w&&typeof w==="object"&&typeof w.toJSON==="function")w=w.toJSON(x);if(typeof C==="function")w=C.call(E,x,w);switch(typeof w){case "string":return I(w);case "number":return isFinite(w)? 
String(w):"null";case "boolean":case "null":return String(w);case "object":if(!w)return"null";p+=c;t=[];if(typeof w.length==="number"&&!w.propertyIsEnumerable("length")){A=w.length;for(x=0;x<A;x+=1)t[x]=J(x,w)||"null";E=t.length===0?"[]":p?"[\n"+p+t.join(",\n"+p)+"\n"+s+"]":"["+t.join(",")+"]";p=s;return E}if(C&&typeof C==="object"){A=C.length;for(x=0;x<A;x+=1){u=C[x];if(typeof u==="string")if(E=J(u,w))t.push(I(u)+(p?": ":":")+E)}}else for(u in w)if(Object.hasOwnProperty.call(w,u))if(E=J(u,w))t.push(I(u)+ 
(p?": ":":")+E);E=t.length===0?"{}":p?"{\n"+p+t.join(",\n"+p)+"\n"+s+"}":"{"+t.join(",")+"}";p=s;return E}}return{stringify:function(x,E,u){E=E;u=u;var A;c=p="";if(typeof u==="number")for(A=0;A<u;A+=1)c+=" ";else if(typeof u==="string")c=u;if((C=E)&&typeof E!=="function"&&(typeof E!=="object"||typeof E.length!=="number"))throw new Error("JSON.stringify");return J("",{"":x})},parse:function(x,E){var u=E;function A(s,t){var w,M,H=s[t];if(H&&typeof H==="object")for(w in H)if(Object.hasOwnProperty.call(H, 
w)){M=A(H,w);if(M!==undefined)H[w]=M;else delete H[w]}return u.call(s,t,H)}i.lastIndex=0;if(i.test(x))x=x.replace(i,function(s){return"\\u"+("0000"+(+s.charCodeAt(0)).toString(16)).slice(-4)});if(/^[\],:{}\s]*$/.test(x.replace(/\\(?:["\\\/bfnrt]|u[0-9a-fA-F]{4})/g,"@").replace(/"[^"\\\n\r]*"|true|false|null|-?\d+(?:\.\d*)?(?:[eE][+\-]?\d+)?/g,"]").replace(/(?:^|:|,)(?:\s*\[)+/g,""))){x=eval("("+x+")");return typeof u==="function"?A({"":x},""):x}throw new Error("JSON.parse");}}}()); 
JSON.parse=function(){var v=JSON.parse;return function(i,m){try{return v(i,m)}catch(p){return false}}}(); 

使用

var bob = { 
      key1: "val1", 
      key2: "val2" 
     } 
console.log(JSON, JSON.stringify(bob), JSON.parse(JSON.stringify(bob)))