1
使用我有一个N1QL查询像如何返回纯数组中的子查询
SELECT RAW ARRAY_AGG(list.id)
FROM default list
WHERE list.type="list"
AND "*" IN list.supported
以下对象(S):
{
"type": "list",
"id": "*",
"name": "Everything",
"listCount": 2,
"supported": [
"*",
"test"
]
}
现在的问题是,我会总是得到一个双阵列的结果:
[
[
"*",
"test"
]
]
我怎么能现在防止双阵列结果或更好:我怎么使用这个结果在下面的子查询(其人方法会返回一个空数组):
SELECT *
FROM default server
WHERE server.type="server" AND ANY listId IN supportedLists SATISFIES
listId in
(SELECT RAW ARRAY_AGG(list.id)
FROM default list
WHERE list.type="list"
AND "*" IN list.supported)
END;
其中服务器是:
{
"type": "server",
"id": "AAABBBCCC",
"supportedLists": [
"0",
"1"
],
}
的选择
SELECT *
FROM default server
WHERE server.type="server" AND ANY listId IN supportedLists SATISFIES
listId in
["test", "other features"]
END;
正常工作...所以我的问题是definetly子选择
我想存档的是有一个支持列表(field supportedList)的服务器列表,例如所有的lis与功能 “测试”(支持的字段)TS