如何每周组如果你有每日数据

Question

我目前坚持这个问题。假设我有以下每日数据

+-------------------------+-----+----+ 
    |   Date   | C1 | C2 | 
    +-------------------------+-----+----+ 
    | 2012-08-01 00:00:00.000 | 44 | 44 | 
    | 2012-08-02 00:00:00.000 | 51 | 49 | 
    | 2012-08-03 00:00:00.000 | 60 | 59 | 
    | 2012-08-04 00:00:00.000 | 68 | 67 | 
    | 2012-08-05 00:00:00.000 | 82 | 78 | 
    | 2012-08-06 00:00:00.000 | 62 | 59 | 
    | 2012-08-07 00:00:00.000 | 58 | 53 | 
    | 2012-08-08 00:00:00.000 | 69 | 65 | 
    | 2012-08-09 00:00:00.000 | 82 | 72 | 
    | 2012-08-10 00:00:00.000 | 70 | 68 | 
    | 2012-08-11 00:00:00.000 | 75 | 71 | 
    | 2012-08-12 00:00:00.000 | 64 | 64 | 
    | 2012-08-13 00:00:00.000 | 74 | 69 | 
    | 2012-08-14 00:00:00.000 | 60 | 56 | 
    | 2012-08-15 00:00:00.000 | 66 | 60 | 
    | 2012-08-16 00:00:00.000 | 57 | 51 | 
    | 2012-08-17 00:00:00.000 | 52 | 49 | 
    +-------------------------+-----+----+ 

我该如何对它进行分组，以便每周总结C1和C2？ 预期的输出应该

+---------------------------+------+----+ 
|   Date    | C1 | C2 | 
+---------------------------+------+----+ 
| 2012-08-06 to 2012-12-12 | 480 | 452| 
| 2012-08-13 to 2012-08-19 | 430 | 394| 
+---------------------------+------+----+ 

它始于2012-08-06以来，周期应该是周一到周日。 我试过Google搜索一个小时左右，似乎没有结果符合我的问题，我希望有人能帮助我。

谢谢！

Answer 1

试试这个：

SET DATEFIRST 1将你的一周的开始设定为周一

SET DATEFIRST 1 

    SELECT CAST(MIN([DATE]) AS VARCHAR(20))+' TO '+CAST (MAX([DATE]) AS VARCHAR(20)) AS DATE, 
      SUM(C1) AS GRU, 
      SUM(C2) AS C1 
    FROM YOUR_TABLE 
    GROUP BY DATEPART(WEEK,[DATE]) 
    HAVING COUNT(DISTINCT[DATE])=7 

SET DATEFIRST 7 

Answer 2

像这样的东西也许（记得要接受一个答案）

declare @t table(Date datetime, C1 int, C2 int) 
insert @t values('2012-08-01',44,44) 
insert @t values('2012-08-02',51,49) 
insert @t values('2012-08-03',60,59) 
insert @t values('2012-08-04',68,67) 
insert @t values('2012-08-05',82,78) 
insert @t values('2012-08-06',62,59) 
insert @t values('2012-08-07',58,53) 
insert @t values('2012-08-08',69,65) 
insert @t values('2012-08-09',82,72) 
insert @t values('2012-08-10',70,68) 
insert @t values('2012-08-11',75,71) 
insert @t values('2012-08-12',64,64) 
insert @t values('2012-08-13',74,69) 
insert @t values('2012-08-14',60,56) 
insert @t values('2012-08-15',66,60) 
insert @t values('2012-08-16',57,51) 
insert @t values('2012-08-17',52,49) 

select 
convert(varchar(10), dateadd(week, datediff(week, 0, date-1),0), 120)+' to '+ 
convert(varchar(10), max(dateadd(week, datediff(week, 0,date-1),6)), 120) Date, 
sum(C1) GRU, sum(C2) C1 
from @t 
group by dateadd(week, datediff(week, 0, date-1),0) 
having datediff(day, 0, min(date)) %7 = 0