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我有一个超过100,000个json文件的列表，我想从中获取data.table只有几个变量。不幸的是这些文件很复杂。每个JSON文件的内容是这样的：从json文件列表到data.table：部分变量列表
样品1
$id
[1] "10.1"
$title
$title$value
[1] "Why this item"
$itemsource
$itemsource$id
[1] "AA"
$date
[1] "1992-01-01"
$itemType
[1] "art"
$creators
list()
样品2
$id
[1] "10.2"
$title
$title$value
[1] "We need this item"
$itemsource
$itemsource$id
[1] "AY"
$date
[1] "1999-01-01"
$itemType
[1] "art"
$creators
type name firstname surname affiliationIds
1 Person Frank W. Cornell. Frank W. Cornell. a1
2 Person David A. Chen. David A. Chen. a1
$affiliations
id name
1 a1 Foreign Affairs Desk, New York Times
我从这组文件需要与制作者姓名，项目ID和日期表。对于上述两个示例文件：
id date name firstname lastname creatortype
"10.1" "1992-01-01" NA NA NA NA
"10.2" "1999-01-01" Frank W. Cornell. Frank W. Cornell. Person
"10.2" "1999-01-01" David A. Chen. David A. Chen. Person
我迄今所做的：
library(parallel)
library(data.table)
library(jsonlite)
library(dplyr)
filelist = list.files(pattern="*.json",recursive=TRUE,include.dirs =TRUE)
parsed = mclapply(filelist, function(x) fromJSON(x),mc.cores=24)
data = rbindlist(mclapply(1:length(parsed), function(x) {
a = data.table(item = parsed[[x]]$id, date = list(list(parsed[[x]]$date)), name = list(list(parsed[[x]]$name)), creatortype = list(list(parsed[[x]]$creatortype))) #ignoring the firstname/lastname fields here for convenience
b = data.table(id = a$item, date = unlist(a$date), name=unlist(a$name), creatortype=unlist(a$creatortype))
return(b)
},mc.cores=24))
然而，在最后一步，我得到这个错误：
"Error in rbindlist(mclapply(1:length(parsed), function(x){:
Item 1 of list is not a data.frame, data.table or list"
在此先感谢为您的建议。 相关的问题包括： Extract data from list of lists [R] R convert json to list to data.table I want to convert JSON file into data.table in r How can read files from directory using R? Convert R data table column from JSON to data table