2009-08-14 53 views
1

我使用SQLAlchemy访问postgres表。我想要查询具有预先加载。SQLAlchemy - 试着渴望加载..属性错误

from sqlalchemy.orm import sessionmaker, scoped_session, eagerload 
from settings import DATABASE_USER, DATABASE_PASSWORD, DATABASE_HOST, DATABASE_PORT, DATABASE_NAME 
from sqlalchemy import create_engine 
from sqlalchemy import Table, Column, Integer, String, Boolean, MetaData, ForeignKey 
from sqlalchemy.orm import mapper 
from sqlalchemy.ext.declarative import declarative_base 

def create_session(): 
    engine = create_engine('postgres://%s:%[email protected]%s:%s/%s' % (DATABASE_USER, DATABASE_PASSWORD, DATABASE_HOST, DATABASE_PORT, DATABASE_NAME), echo=True) 
    Session = scoped_session(sessionmaker(bind=engine)) 
    return Session() 

Base = declarative_base() 
class Zipcode(Base): 
    __tablename__ = 'zipcode' 
    zipcode = Column(String(6), primary_key = True, nullable=False) 
    city = Column(String(30), nullable=False) 
    state = Column(String(30), nullable=False) 

session = create_session() 
query = session.query(Zipcode).options(eagerload('zipcode')).filter(Zipcode.state.in_(['NH', 'ME'])) 
#query = session.query(Zipcode.zipcode).filter(Zipcode.state.in_(['NH', 'ME'])) 
print query.count() 

这种失败 AttributeError的: 'COLUMNPROPERTY' 对象有没有属性 '映射'

一个没有正确eagerloading返回记录。

我是SQLAlchemy的新手。我不确定问题是什么。任何指针?

+0

您是否有此初学者代码的链接可能描述此代码的工作原理? – sAguinaga 2017-06-15 10:27:46

回答

2

您只能急切地加载关系属性。不在桌子上。急切加载意味着在获取特定对象的同时从其他表中加载对象。加载查询的所有对象的方式将简单地添加all()。

query = session.query(Zipcode).options(eagerload('zipcode')).filter(Zipcode.state.in_(['NH', 'ME'])).all() 

该查询现在将是表中所有对象(行)的列表,并且len(query)将为您提供计数。

+0

是的..谢谢我混在一起.. – Ramya 2009-08-14 21:40:13