在邮政编码和距离的基础上搜索类别

Question

我在邮编和距离的基础上搜索类别。我希望得到特定类别的结果，并在该邮编的10英里无线电收音机中播放。

我的表格式

CREATE TABLE IF NOT EXISTS `uk_data` (
    `slno` int(10) NOT NULL AUTO_INCREMENT, 
    `comp_name` varchar(150) DEFAULT NULL, 
    `comp_no` varchar(50) DEFAULT NULL, 
    `comp_street` varchar(100) DEFAULT NULL, 
    `comp_area` varchar(100) DEFAULT NULL, 
    `comp_post_code` varchar(15) DEFAULT NULL, 
    `comp_phone` varchar(100) DEFAULT NULL, 
    `comp_phone1` varchar(100) DEFAULT NULL, 
    `cat1` varchar(100) DEFAULT NULL, 
    `cat2` varchar(100) DEFAULT NULL, 
    `cat3` varchar(100) DEFAULT NULL, 
    `cat4` varchar(100) DEFAULT NULL, 
    `cat5` varchar(100) DEFAULT NULL, 
    `cat6` varchar(100) DEFAULT NULL, 
    `cat7` varchar(100) DEFAULT NULL, 
    `cat8` decimal(9,6) DEFAULT NULL, 
    `cat9` decimal(9,6) DEFAULT NULL, 
    `cat10` varchar(15) DEFAULT NULL, 
    PRIMARY KEY (`slno`), 
    UNIQUE KEY `Phone` (`comp_phone`), 
    KEY `cat10` (`cat10`) 
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=31717 ; 

现在

cat10 is postcode 

cat8 is Latitude 

cat9 is Longitude 

我能计算出的距离，并得到一个纬度和经度的特定英里范围内导致这里是

SELECT cat10, (3959 * acos(cos(radians({$coords['Latitude']})) 
* cos(radians(cat8)) * cos(radians(cat9) - radians({$coords['Longitude']})) 
+ sin(radians({$coords['Latitude']})) * sin(radians(cat8)))) 
AS distance FROM uk_data 
HAVING distance <= {$radius} ORDER BY distance 

$coords = array('Latitude' => "57.149727", 'Longitude' => "-2.094735"); 
$radius = .5;  
$uk_data_radious = uk_data_radious_test($coords,$radius,$q,$pc); 

现在我正在试图通过邮编的特定距离获得完整的搜索范围。

SELECT *, (3959 * acos(cos(radians({$coords['Latitude']})) * cos(radians(cat8)) * cos(radians(cat9) - radians({$coords['Longitude']})) + sin(radians({$coords['Latitude']})) * sin(radians(cat8)))) AS distance 
    FROM uk_data where 
     cat1 like :cat OR 
     cat2 like :cat OR 
     cat3 like :cat OR 
     cat4 like :cat OR 
     cat5 like :cat OR 
     cat6 like :cat OR 
     cat7 like :cat 
    HAVING distance <= {$radius} 
    ORDER BY distance 

但这不起作用。我知道有在查询时出现错误，但不知道如何与HAVING和地点处理该查询一起为3个参数Postcode Distance and categories

错误

Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42000]: Syntax error 
or access violation: 1064 You have an error in your SQL syntax; check the manual that 
corresponds to your MySQL server version for the right syntax to use near ':cat OR cat2 
like :cat OR cat3 like :cat OR cat4 like :cat OR ' at line 4' in 
D:\Winginx\home\****\public_html\functions.php:365 Stack trace: #0 
D:\Winginx\home\****\public_html\functions.php(365): PDO->query('SELECT *, (395...') #1 
D:\Winginx\home\***\public_html\miles_output.php(14): uk_data_radious_test(Array, 0.5, 
'Tool') #2 {main} thrown in D:\Winginx\home\***\public_html\functions.php on line 365 

Answer 1

我finaly找到sulution我的问题....但我觉得可能是更好的方法来做到这一点...我还是想在这里分享答案，所以如果有人正在寻找相同的答案可能会得到帮助，是的，如果有一个人有更好的方式来做到这一点请建议THX

这里我在做什么

1化妆功能

function distance($lat1, $lon1, $lat2, $lon2, $unit) { //** this to calculate distance in Miles or Km 

     $theta = $lon1 - $lon2; 
     $dist = sin(deg2rad($lat1)) * sin(deg2rad($lat2)) + cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta)); 
     $dist = acos($dist); 
     $dist = rad2deg($dist); 
     $miles = $dist * 60 * 1.1515; 
     $unit = strtoupper($unit); 

     if ($unit == "K") { 
     return ($miles * 1.609344); 
     } else if ($unit == "N") { 
      return ($miles * 0.8684); 
     } else { 
      return $miles; 
      } 
    } 


     function uk_data_radious($coords, $radius){//** this to get result within certain radios for a postcode 
     global $DBH; 
     $STH = $DBH->prepare("SELECT DISTINCT cat10, (3959 * acos(cos(radians({$coords['Latitude']})) 
        * cos(radians(cat8)) 
        * cos(radians(cat9) - radians({$coords['Longitude']})) 
        + sin(radians({$coords['Latitude']})) 
        * sin(radians(cat8)))) AS distance FROM uk_data HAVING distance <= {$radius} ORDER BY distance"); 
     $STH->bindValue(':postcode', "$postcode", PDO::PARAM_STR); 
     $STH->setFetchMode(PDO::FETCH_ASSOC); 
     $STH->execute(); 
     return $STH; 
    } 

     function uk_data_pc_count($user_count){//*** this is to check if post code is in our database or not 
     global $DBH; 
     $STH = $DBH->prepare("SELECT * from uk_data where cat10 = :user_count"); 
     $STH->bindValue(':user_count', $user_count, PDO::PARAM_STR); 
     $STH->execute(); 
     $row_count = $STH ->rowCount(); 
     return $row_count ; 
    } 

function comp_post_code($cat, $comp_post_code){//** this to get result within postcode 
    global $DBH; 
    $STH = $DBH->prepare("SELECT * from uk_data where 
          cat10 like :comp_post_code AND (
          cat1 like :cat OR 
          cat2 like :cat OR 
          cat3 like :cat OR 
          cat4 like :cat OR 
          cat5 like :cat OR 
          cat6 like :cat OR 
          cat7 like :cat OR 
          cat8 like :cat OR 
          cat9 like :cat 
          )") ; 
    $STH->bindValue(':cat', "%$cat%", PDO::PARAM_STR); 
    $STH->bindValue(':comp_post_code', "$comp_post_code%", PDO::PARAM_STR); 
    $STH->execute(); 
    $STH->setFetchMode(PDO::FETCH_ASSOC); 
    return $STH; 
    } 

现在使用页面上

$q = $_GET['id']; 
$pc = change_text(' ', '',$_GET['pc']); 
$qu = change_text(' ', '%', $q); 
$pc_o = array(); 
$comp_name = array(); 
$comp_phone = array(); 
$distance = array(); 
$Latitude = array(); 
$Longitude = array(); 
$post_code = array(); 

if(uk_data_pc_count($pc) > 0 ){ 

$uk_data_ll = uk_data_ll($pc); 
while (($row = $uk_data_ll->fetch()) !== false) { 
$Latitude[] = $row['cat8']; 
$Longitude[] = $row['cat9']; 

} 

$coords = array('Latitude' => "$Latitude[0]", 'Longitude' => "$Longitude[0]"); 
$radius = 10; 

$uk_data_radious = uk_data_radious($coords,$radius,$q); 
while (($row = $uk_data_radious->fetch()) !== false) { 
    /*echo $row['cat10'].' --- '.$row['distance'].'<br>';*/ 
    $pc_o[] = $row['cat10']; 
    $distance[] = $row['distance']; 

} 
foreach($pc_o as $pc_o){ 
$uk_data_radious = comp_post_code($q,$pc_o); 
while (($row = $uk_data_radious->fetch()) !== false) { 
$comp_name[] = $row['comp_name']; 
$comp_phone[] = $row['comp_phone']; 
$post_code[] = $row['cat10']; 
$distance_m[] = distance($Latitude[0],$Longitude[0],$row['cat8'],$row['cat9'],"M"); 
}} 



for($i=0, $count = count($comp_name);$i<$count;$i++) { 
    echo $post_code[$i].' - '.$comp_name[$i].' - '.$comp_phone[$i].' - '.round($distance_m[$i],2).' Miles<br>'; 
    } 
}else {echo 'Wrong Post-Code Selected';} 

THX希望这将有助于和希望得到很好的建议;）

Answer 2

尝试输出错误信息。

我不知道，但我觉得你不需要使用具有，只是周围使用（OR ..）部分这样的括号：

SELECT *, (3959 * acos(cos(radians({$coords['Latitude']})) * cos(radians(cat8)) * cos(radians(cat9) - radians({$coords['Longitude']})) + sin(radians({$coords['Latitude']})) * sin(radians(cat8)))) AS distance 
FROM uk_data where 
    (
    cat1 like :cat OR 
    cat2 like :cat OR 
    cat3 like :cat OR 
    cat4 like :cat OR 
    cat5 like :cat OR 
    cat6 like :cat OR 
    cat7 like :cat 
    ) AND distance <= {$radius} 
ORDER BY distance 

作为一个侧面说明，它是糟糕的设计，每个类别都有一张表格;每次添加新类别时，都需要更改sql表结构。