获得行驶距离的邮政编码，以在上述功能“fxnGetNearestDealer” V3

Question

 fxnGetNearestDealer: function() { 

      //Gets LatLng for given Zipecode and displays the dealer. 
      fxnGetLatLngforZip(function() { 
       //Gets The Nearest Dealers Index out of dealers in the site. 
       fxnGetNearDealerIndex(function (distance) { 
        alert(distance); 
        //Gets Html To Display NearestDealer Details. 
        sHtml = fxnGetHtmlforNearestDealer(); 

        //Displays Nearest Dealer Details in the span with Id "spanDNAddr". 
        document.getElementById('spanDNAddr').innerHTML = sHtml; 
       }); 
      }); 
     }; 

fxnGetLatLngforZip = function (callback) { 
     var oGeocoder = new google.maps.Geocoder(), 
      iZipcode = document.getElementById('txtZipCode').value; 

     //Boundary checks 
     if (!iZipcode) { return; } 

     oGeocoder.geocode({ 'address': iZipcode }, function (result, status) { 
      if (status == google.maps.GeocoderStatus.OK) { 
       g_oLatLng = result[0].geometry.location; 
       callback(); 
      } 
      else { 
       //Can use status its self to display the error message. 
       document.getElementById('spanDNAddr').innerHTML = "No Results Found Enter Valid ZipCode"; 
      } 
     }); 
    }; 

fxnGetNearDealerIndex = function (callback) { 
     //Boundary Checks 
     if (!g_oLatLng) { return; } 

     var oDealerLatlng = null, 
      dDistance = null, 
      tempindex = null, 
      dTemp = null; 

     for (var iAddrIdx = 0; iAddrIdx < g_oAddrs.length; iAddrIdx++) { 
      oRequest = { 
       origin: g_oLatLng, 
       destination: new google.maps.LatLng(g_oAddrs[iAddrIdx].latitude, g_oAddrs[iAddrIdx].longitude), 
       travelMode: google.maps.TravelMode.DRIVING 
      }; 

      g_oDirections.route(oRequest, function (response, status) { 
       if (status == google.maps.DirectionsStatus.OK) { 
        dDistance = response.routes[0].legs[0].distance.value; 
        if (!dTemp) { 
         dTemp = dDistance; 
        } 
        else if (dDistance < dTemp) { 
         dTemp = dDistance; 
         g_iNearIndex = iAddrIdx; 
        } 
       } 
      }); 
     } 
     callback(dTemp); 
    }; 

多邮编为起点从那里我想获得经纬度给定邮编因为这将是一个异步调用，我用了回调它的工作正常..在我必须做另一个异步调用来计算给定的zipcode latlng和forLoop中迭代的每个latlng之间的驱动距离。并获得最小值。我结束了像上面写的....它永远不会返回的问题它在alert中给出null的任何值。如果我在萤火虫中看到它迭代所有时间请求创建好，但它永远不会进入“g_oDirections.route”函数，因为它是异步我使用回调，但它没有工作....任何工作围绕PLZ ... ...

Answer 1

下面的例子是通用的。它展示了如何从曼哈顿的一个点到多个邮政编码的距离。

var dirService = new google.maps.DirectionsService(); 

//Hold all destinations in an array 
var destinations = ['10001', '10002', '10003']; 

//Start from somewhere in Manhattan 
var startLocation = new google.maps.latLng(40.769102, -73.971176); 



function drivingDistance(start, end) { 
var request = { 
    origin: start, 
    destination: end, 
    travelMode: google.maps.TravelMode.DRIVING 
    }; 

    //Use a separate named function as callback(not anonymous inline) 
    dirService.route(request, routeCallback); 

} 

//callback function 
function routeCallback(result, status) { 
    if (status == google.maps.DirectionsStatus.OK){ 

     alert(result.routes[0].legs[0].duration.text); 

      //alternative: 
      //alert(result.routes[0].legs[0].distance.text); 

     //If success then remove the first destination from the array and execute the next request 
     destinations.shift(); 
     getnextRoute(); 
    } 
} 

function getnextRoute(){ 
    if(destinations.length){ 
     drivingDistance(startLocation, destinations[0]); 
    } 
} 


// Start executing 
getnextRoute();