在SQL中结合IN和NOT IN作为单一结果

对于模糊标题，我表示歉意。我正在尝试编写一个查询，该查询返回具有匹配值（由IN产生）的别名列以及具有不匹配值（使用NOT IN）的别名列。我希望结果集具有：userId |匹配| nonmatches。我目前有以下查询返回匹配如预期。我遇到麻烦nonmatches结果集 - 也就是说，从NOT IN声明在SQL中结合IN和NOT IN作为单一结果

SET @userId = 9; 
SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches 
FROM user_goal ug 
WHERE [email protected] 
AND goal_id IN (SELECT iug.goal_id FROM user_goal iug WHERE [email protected]) 
GROUP BY user_id ORDER BY matches DESC LIMIT 4

因此，NOT IN会是这个样子：

goal_id NOT IN(SELECT uggg.goal_id FROM user_goal uggg WHERE [email protected]) AS nonmatches

我只是不确定如何把NOT IN语句在我的查询，所以我得到的所有结果

来源

2010-04-22 RyanLynch

试试这个（可以简化并进一步优化如果MySQL有CTE虽然）：

select u.user_id, the_matches.matches, the_nonmatches.nonmatches 
from user u 
left join 
( 
    SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches 
    FROM user_goal ug 
    WHERE [email protected] 
    AND goal_id IN (SELECT iug.goal_id FROM user_goal iug WHERE [email protected]) 
    GROUP BY user_id 
    ORDER BY matches DESC LIMIT 4 
) as the_matches on the_matches.user_id = u.user_id 
left join 
(
    SELECT ug.user_id, COUNT(DISTINCT goal_id) as nonmatches 
    FROM user_goal ug 
    WHERE [email protected] 
    AND goal_id NOT IN(SELECT uggg.goal_id FROM user_goal uggg WHERE [email protected]) 
    GROUP BY user_id 
) as the_nonmatches on the_nonmatches.user_id = u.user_id

来源

2010-04-22 14:01:26

通过彼此PARAM组它，修复，如果有从子查询的目标，这将被用于一个PARAM

来源

2010-04-22 13:44:31

我不知道我明白你的意思了“修理一个参数”，你能解释一下吗？ – RyanLynch 2010-04-22 13:46:15

只是检查返回的目标是否属于用户，然后将某些值设置为“1”，否则将其设置为“0”，并且seted值可以具有别名“x” ，以便您可以按照user_id，x – 2010-04-22 14:00:32

对它们进行分组我不明白回答。 – Jodrell 2012-11-15 11:15:07

，我认为联合是你所需要的：

SET @userId = 9; 

SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches 
FROM user_goal ug 
WHERE [email protected] 
AND goal_id IN (SELECT iug.goal_id FROM user_goal iug WHERE [email protected]) 
GROUP BY user_id ORDER BY matches DESC LIMIT 4 

union all 

SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches 
FROM user_goal ug 
WHERE [email protected] 
AND goal_id NOT IN(SELECT uggg.goal_id FROM user_goal uggg WHERE [email protected]) 
GROUP BY user_id ORDER BY matches DESC LIMIT 4

来源

2010-04-22 13:45:57 Ray

谢谢，有什么我需要改变GROUP BY？ – RyanLynch 2010-04-22 13:58:49

我不这么认为，如果你的选择列表对于查询的两个部分是相同的。我不是一个mysql的人，所以我不知道是否有其他需求，我错过了，但它看起来像标准的东西给我。 – Ray 2010-04-22 14:09:11

在SQL中结合IN和NOT IN作为单一结果

回答

相关问题