PHP更新查询失败my_fetch_array

-3

这里是我的我的editsupplier表单代码

<?php 
$SupplierID = $_GET['SupplierID'] = $row['SupplierID']; 
//Connect and select a database 
mysql_connect ("localhost", "root", ""); 
mysql_select_db("supplierdetails"); 
//Run query 
$result1 = mysql_query("SELECT * FROM suppliers WHERE SupplierID=$SupplierID"); 
while($row = mysql_fetch_array($result1)){ 
$SupplierID = $_GET['SupplierID'] = $row['SupplierID']; 
$SupplierName = $row['SupplierName']; 
$Currency = $row['Currency']; 
$Location = $row['Location']; 
$ContactNumber = $row['ContactNumber']; 
$Email = $row['Email']; 
    } 
?> 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1- strict.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> 
<head> 
<meta http-equiv="content-type" content="text/html; charset=utf-8" /> 
<meta name="description" content="" /> 
<meta name="keywords" content="" /> 
<meta name="author" content="" /> 
<link rel="stylesheet" type="text/css" href="style.css" media="screen" /> 
<title>Harrison Spinks</title> 
    </head> 
    <body> 
    <div id="wrapper"> 
<?php include('includes/header.php'); ?> 
<?php include('includes/nav.php'); ?> 
<div id="content"> 
<h3><center>Edit Supplier Information</center></h3> 
<p>Please enter all the following details to edit a supplier</p> 
</div> 
<div> 
<br> 
</br> 
<form action="Edit_Supp.php" method="post"> 
<br> 
</br> 
<input type="hidden" name="SupplierID" value="<?php echo $SupplierID;?>"/> 

Supplier Name: <input type="text" name="SupplierName" value="<?php echo $SupplierName ;?>" /> 
<br> 
</br> 
Currency: <input type="text" name="Currency" value="<?php echo $Currency ;?>" /> 
<br> 
</br> 
    Location: <input type="text" name="Location" value="<?php echo $Location ;?>" /> 
    <br> 
    </br> 
Contact Number:<input type="text" name="ContactNumber" value="<?php echo $ContactNumber ;?>" /> 
<br> 
</br> 
Email:<input type="text" name="Email" value="<?php echo $Email ;?>" /> 
<br> 
</br> 
<input type="submit" value= "Edit Supplier Information"/> 

</form> 
</div> 
</body> 
</html>

错误是内更新我的供应商信息：

Notice: Undefined variable: row in E:\xampp\htdocs\EditSupForm.php on line 2 
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in E:\xampp\htdocs\EditSupForm.php on line 8

这是表格背后的代码：

<?php 
$con = mysql_connect("localhost", "root", ""); 
    mysql_select_db("supplierdetails"); 
     if (!$con)  
      {  
     die('Could not connect: ' . mysql_error());   
     }  
    //Run a query   
    $SupplierID= $_POST['SupplierID'] = $row ["SupplierID"]; 
$result1 = mysql_query ("SELECT * FROM suppliers WHERE SupplierID= '".$SupplierID."'")   or die(mysql_error());  
$row = mysql_fetch_array($result1); 
$SupplierID = $_POST['SupplierID'] = $row ["SupplierID"]; 
$SupplierName = $_POST['SupplierName']; 
$Currency = $_POST['Currency']; 
$Location = $_POST['Location']; 
$ContactNumber = $_POST['ContactNumber']; 
$Email = $_POST['Email']; 
$SupplierID = $row['SupplierID'];   
    $query = "UPDATE suppliers SET SupplierID = '".$SupplierID."', SupplierName= '".$SupplierName."', Currency = '".$Currency."', Location = '".$Location."', ContactNumber = '".$ContactNumber."', Email = '".$Email."' WHERE SupplierID = '".$id."'";  
$result1 = mysql_query($query);   
//Check whether the query was successful or not  
if($result1) 
{   
echo "Supplier Updated"; 
header ("Location: Supplier.php");  
} 
else 
{   
die ("Query failed");  
    }  
?>

来源

2012-04-20 Natalie Webb

$ row is undefined ... – 2012-04-20 09:28:18

我在哪里定义这个？如何？ – 2012-04-20 09:29:01

在第2行，并检查我的回答 – 2012-04-20 09:31:50

在执行mysql查询之前，您使用的两个代码都是$row ["SupplierID"];，`$ row [“SupplierID”];'这就是为什么你会得到错误。

来源

2012-04-20 09:45:53

PHP更新查询失败my_fetch_array

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