集团在子查询

我在那有一个表AssignmentMaster我有一个数据集团在子查询

AssignmentID   PaidAmount  RefundAmount UserID 
1      20    0    1 
2      10    5    1 
3      30    7    2 
4      25    0    3 
5      35    15    3 
6      10    3    1 
7      5    0    3 
8      10    0    3

现在我想找出相对于用户ID的TotalNumberofAssignment以下几列，即结果应该是：

UserID TotalAssignment TotalAssignmentofRefundAmount TotalPaidAmount TotalRefundAmount 
1    3     2      40    8 
2    1     1      30    7 
3    4     1      75    15

如何在MSSQL中获得以上结果。你的任何帮助将帮助我很多。

来源

2011-06-14 Vijjendra

SELECT 
    UserID, 
    COUNT(AssignmentID) AS TotalAssignment, 
    SUM(SIGN(RefundAmount)) AS TotalAssignmentofRefundAmount, 
    SUM(PaidAmount) AS TotalPaidAmount, 
    SUM(RefundAmount) AS TotalRefundAmount 
FROM 
    MyTable 
GROUP BY 
    UserID

注：

SIGN(RefundAmount)作品如果REFUNDAMOUNT总是> = 0

如果没有，更改为

SUM(CASE WHEN RefundAmount <> 0 THEN 1 ELSE 0 END) AS TotalAssignmentofRefundAmount

来源

2011-06-14 12:21:23 gbn

“SIGN”解决方案的+1。 – 2011-06-14 12:24:23

对于新的sql关键字（SIGN）+1，你能告诉我SIGN是如何工作的吗？谢谢Vijendra – Vijjendra 2011-06-14 12:29:03

SIGN与ABS（x）/ x相同。当x> 0时，SIGN（x）= 1。当x <0时，SIGN（x）= -1。 SIGN（0）= 0. – UltraCommit 2011-06-14 12:31:32

Select UserID, 
     count(1) as TotalAssignment, 
     sum(case when RefundAmount = 0 then 0 else 1 end) as TotalAssignmentofRefundAmount, 
     sum(PaidAmount) as TotalPaidAmount , 
     sum(RefundAmount) as TotalRefundAmount 
From AssignmentMaster 
Group by UserID

来源

2011-06-14 12:22:17

select UserId, count (AssignmentID) as TotalAssignment, 
sum(case when RefundAmount = 0 then 0 else 1 end) as TotalAssignmentofRefundAmount, 
sum(PaidAmount) as TotalPaidAmound, 
sum(RefundAmount) as TotalRefundAmount 
from AssignmentMaster 
group by UserID;

来源

2011-06-14 12:25:31 UltraCommit

AFAIK，SQL Server没有'DECODE'功能，即Oracle特定的语法。您可以将其更改为“CASE”声明。 – 2011-06-14 12:27:09

刚刚更正，谢谢。 – UltraCommit 2011-06-14 12:27:52

此外，您可能需要将用户ID添加到选择列表中以提高结果的可读性。 – eftpotrm 2011-06-14 13:37:56

为了显示怎么办这使用嵌套的SQL：

Select UserTotals.UserID, UserTotals.TotalAssignment, 
     Refunds.TotalAssignmentofRefundAmount, 
     UserTotals.TotalPaidAmount, UserTotals.TotalRefundAmount 
From (select  UserID, 
        Count(AssignmentID) [TotalAssignment], 
        Sum(PaidAmount)  [TotalPaidAmount], 
        sum(RefundAmount) [TotalRefundAmount] 
        From  @AssignmentMaster 
        Group By UserID 
     ) [UserTotals] Left Join 
     (Select  UserID, 
        Count(AssignmentID) [TotalAssignmentofRefundAmount] 
        From  @AssignmentMaster 
        Where  RefundAmount > 0 
        Group By UserID 
     ) [Refunds] On Refunds.UserID = UserTotals.UserID

来源

2011-06-14 12:37:52 pingoo

集团在子查询

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