2011-09-07 55 views
1

在我的应用程序中,我使用SwingX库中的JXButton,我非常喜欢画家方法。现在,我必须将我的简单按钮更改为切换按钮,并为未选定/选定状态设置不同的画家。不幸的是我找不到JXToggleButton。是否有解决方案来保持画家方法的好处?SwingX和JToggleButton

回答

0

创建JXType组件实际上相当简单。您可能需要对边框,焦点等进行额外检查。但这是您将采取的一般方法

public class JXToggleButton extends JToggleButton implements FocusListener, Paintable { 
    private Painter<JTextField> backgroundPainter; 
    private Painter<JTextField> foregroundPainter; 

    public void setBackgroundPainter(Painter<JTextField> painter) { 
     this.backgroundPainter = painter; 
    } 

    public void setForegroundPainter(Painter<JTextField> painter) { 
     this.foregroundPainter = painter; 
    } 

    @Override 
    protected void paintComponent(Graphics g) { 

     if (backgroundPainter != null) { 
      this.backgroundPainter.paint((Graphics2D) g, this, getWidth(), getHeight()); 
     } 

     super.paintComponent(g); 

     if (foregroundPainter != null) { 
      foregroundtPainter.paint((Graphics2D) g, this, getWidth(), getHeight()); 
     } 

    } 
}