1
嗨,我有一个xml格式从Web服务生成以下格式。如何将xml解析成java对象?
<root>
<item>
<name>test</name>
<description>test description</description>
<link>http://xxx</link>
</item>
</root>
我读文件
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new URL(url).openStream());
现在我有医生,我怎么会得到和每个
,并把它变成一个对象调用项目
public class Item {
private final String name;
private final String desc;
private final String link;
public Item(final String name, final String desc, final String link) {
super();
this.name = name;
this.desc = desc;
this.link = link;
}
// ... getters for name and desc
}
我看了dom元素的例子,但看起来很混乱。什么是将XML解析为java对象的最简单/有效的方法。我能举个例子吗?
使用xstream工程。
我做
final XStream xstream = new XStream(new DomDriver());
xstream.alias("root", LineItem.class);
xstream.aliasField("name", Item.class, "name");
xstream.aliasField("description", Item.class, "desc");
xstream.aliasField("link", Item.class, "link");
xstream.fromXml(xml);
您正在使用哪种编程语言?如果是java,你可以使用JAXB,这里有一个很好的例子吗? http://www.javabeat.net/articles/14-java-60-features-part-2-pluggable-annotation-proce-3.html – kosa 2012-01-16 16:35:13