XML解析成对象

的名单我想解析任何XML文件到使用 “的SAXParser”XML解析成对象

XMLNode类 “的XMLNode” 类的对象列表

public class XMLNode { 

    private String nodeName; 
    private String nodeValue; 
    private List<XMLNodeAttribute> attributes; 
    private boolean isParentNode; 
    private List<XMLNode> childNodes; 

    //.... getters and setters .... 
}

XMLNodeAttribute类

public class XMLNodeAttribute { 

    private String name; 
    private String value; 

    //.... getters and setters .... 

}

请帮我编写一个解析器类，它可以将输入作为XML文件输出并输出List。

预先感谢您。

我能够写一些代码..

public class XmlProcesser extends DefaultHandler { 

    XMLResponse xmlResponse = null; 
    List<XMLNode> resplist = new ArrayList(); 
    List<XMLNode> temp = new ArrayList(); 
    boolean endtag = false; 

    @Override 
    public void startElement(String uri, String localName, String qName, 
      Attributes attributes) throws SAXException { 

     String elementName = localName; 
      if ("".equals(elementName)) { 
       elementName = qName; 
      } 
     System.out.println(" Start Ele - " + elementName ); 

     //Each attribute 

     if (elementName!=null) { 
      if (attributes!=null) { 
        for (int pos=0; pos<attributes.getLength(); pos++) { 
         String name = attributes.getLocalName(pos)==null || attributes.getLocalName(pos).trim().length()==0 ? attributes.getQName(pos) : attributes.getLocalName(pos); 
         String value= attributes.getValue(pos); 
         System.out.println(" name - " + name + " value - " + value ); 
        } 
       } 
     } 

    } 

    @Override 
    public void characters(char ch[], int start, int length) throws SAXException { 

     String s = new String(ch, start, length); 
     System.out.println(" value - " + s ); 

     endtag = false; 
    } 

    @Override 
    public void endElement(String uri, String localName, 
      String qName) throws SAXException { 
     endtag = true; 

     String elementName = localName; 
      if ("".equals(elementName)) { 
       elementName = qName; 
      } 
     System.out.println(" End Ele - " + elementName ); 

    } 
}

来源

2012-08-02 user1483570

很高兴能帮到你，到目前为止你做了什么？ – talnicolas 2012-08-02 19:33:51

这是与你以前的问题，[XML翻译使用Java Swing]（http://stackoverflow.com/questions/11782785/xml-translator-using-java-swing）？ – trashgod 2012-08-02 19:37:49

你可以使用JAXB的UnmarshallerHandler实现这个用例：

JAXBContext jc = JAXBContext.newInstance(XmlNode.clas); 
    Unmarshaller unmarshaller = jc.createUnmarshaller(); 
    UnmarshallerHandler handler = unmarshaller.getUnmarshallerHandler(); 

    SAXParserFactory spf = SAXParserFactory.newInstance(); 
    SAXParser sp = spf.newSAXParser(); 
    XMLReader xr = sp.getXMLReader(); 
    xr.setContentHandler(handler); 
    xr.parse(xml); 
    XmlNode xmlNode = (XmlNode) handler.getResult();

完整的例子

http://blog.bdoughan.com/2011/05/jaxb-and-dtd.html

来源

2012-08-02 19:42:08

XML解析成对象

回答

相关问题