如何从另一个表

Question

插入带有名字的价值，我希望从我的用户表的列名与用户提交其他信息（profile_img）插入到我的消息表中列名（profile_img1）的值。

这里是我使用至今的查询

$name=$_REQUEST["title"]; 
$stdate=$_REQUEST["sdate"]; 
$endate=$_REQUEST["edate"]; 
$staddr=$_REQUEST["staddr"]; 
$addr2=$_REQUEST["staddr2"]; 
$city=$_REQUEST["city"]; 
$state=$_REQUEST["state"]; 
$zip=$_REQUEST["zip"]; 
$desc=$_REQUEST["desc"]; 
$file=$_REQUEST['photo']; 
$link=$_REQUEST["link"]; 
$user=$_REQUEST["user"]; 
$profile_img1=$_REQUEST["profile_img1"]; 
$rsvp=$_REQUEST["rsvp"];   

$query = "INSERT INTO news (fname,stdate,endate,addr1,addr2,city,state,zip,name,size,type,content,link,description,user,profile_img1,rsvp) VALUES('" . mysql_real_escape_string($name) . "','$stdate','$endate','" . mysql_real_escape_string($staddr) . "','" . mysql_real_escape_string($addr2) . "','" . mysql_real_escape_string($city) . "','$state','$zip','".str_replace([",",":","\"","\\", "/", "*"," ","$","&","?",";","'","!","(",")","|","~","<",">","=","[","]","{","}","#","^","%","=","@","+","è","é"],"",$name) ."-".$stdate."-".$file."','0',' ',' ','" . mysql_real_escape_string($link)."','" . mysql_real_escape_string($desc) . "','$user','" . mysql_real_escape_string($rsvp)."')"; 

为profile_img1在查询用户价值后会去的名字，但我无法弄清楚如何在用户获得profile_img的名字表的消息表

这里是我一直在努力：

$query = "INSERT INTO news (fname,stdate,endate,addr1,addr2,city,state,zip,name,size,type,content,link,description,user,profile_img1,rsvp) VALUES('" . mysql_real_escape_string($name) . "','$stdate','$endate','" . mysql_real_escape_string($staddr) . "','" . mysql_real_escape_string($addr2) . "','" . mysql_real_escape_string($city) . "','$state','$zip','".str_replace([",",":","\"","\\", "/", "*"," ","$","&","?",";","'","!","(",")","|","~","<",">","=","[","]","{","}","#","^","%","=","@","+","è","é"],"",$name) ."-".$stdate."-".$file."','0',' ',' ','" . mysql_real_escape_string($link)."','" . mysql_real_escape_string($desc) . "','$user','(SELECT profile_img FROM users WHERE username=`username`)''" . mysql_real_escape_string($rsvp)."')"; 

使用这种方法会导致profile_img1列在新闻来读取表（SELECT PROFIL e_img从用户其中username = username），而不是什么profile_img列在用户表中读取。

另外，如果我添加第二个INSERT查询

$q2 = mysql_query("INSERT INTO news (profile_img1) SELECT profile_img FROM users WHERE username='username'"); 

查询导致了新的行中只显示来自用户表profile_img，从其他数据的用户会进入独立的消息表中创建。

我希望的结果是让用户将数据提交给新闻表，并将来自用户表的用户图像插入行中的新闻表中，并提交其他数据，以便提交数据和用户图像一起显示。

如果您需要更多的澄清，请让我知道

Answer 1

你不已经有profile_img1价值？

$profile_img1=$_REQUEST["profile_img1"]; 

但无论如何，当然，如果你做2插入它会插入2行。

你要查找更新。

而mysql_insert_id（）得到执行的最后插入的ID。

如（末，后你知道你在做什么）：

UPDATE news SET profile_img1 = "whateveritis" where id = theidoftherowyoujustinserted 

Answer 2

简短的回答是做INSERT（...）SELECT ...

例如

$name=$_REQUEST["title"]; 
$stdate=$_REQUEST["sdate"]; 
$endate=$_REQUEST["edate"]; 
$staddr=$_REQUEST["staddr"]; 
$addr2=$_REQUEST["staddr2"]; 
$city=$_REQUEST["city"]; 
$state=$_REQUEST["state"]; 
$zip=$_REQUEST["zip"]; 
$desc=$_REQUEST["desc"]; 
$file=$_REQUEST['photo']; 
$link=$_REQUEST["link"]; 
$user=$_REQUEST["user"]; 
$profile_img1=$_REQUEST["profile_img1"]; 
$rsvp=$_REQUEST["rsvp"];   

$query = "INSERT INTO news (fname,stdate,endate,addr1,addr2,city,state,zip,name,size,type,content,link,description,user,profile_img1,rsvp) SELECT '" . 
    mysql_real_escape_string($name) . "','$stdate','$endate','" . mysql_real_escape_string($staddr) . 
    "','" . mysql_real_escape_string($addr2) . "','" . mysql_real_escape_string($city) . "','$state','$zip','". 
    str_replace([",",":","\"","\\", "/", "*"," ","$","&","?",";","'","!","(",")","|","~","<",">","=","[","]","{","}","#","^","%","=","@","+","è","é"],"",$name) . 
    "-".$stdate."-".$file."','0',' ',' ','" . mysql_real_escape_string($link)."','" . mysql_real_escape_string($desc) . 
    "',provile_img,'" . 
    mysql_real_escape_string($rsvp)."'" . 
    " FROM users WHERE username = '{$username}'"; 

这应该变成这样的：

INSERT INTO news (fname, stdate, profile_img1, rsvp) 
SELECT 'Bob', '2017-09-02', profile_img, 0 
FROM users 
WHERE username = 'jimbob' 

长的答案涉及恳求不要做自己的逃逸，并重新构造此位，使其更易于阅读，并推而广之，更容易维护后