的MySQL/phpMyAdmin的查询行数（1行）VS mysql_num_rows'伯爵（0行数）

Question

这里是有问题的代码：

<?php // If search option is selected 
include 'db_connect.php'; 

database_connect(); 
$limit = 5; // No of result per page 
$criteria = 1; // Search criteria 
$allResults=array(); // Array of results 
$searchOption = $_REQUEST['searchoption']; 
$searchField = $_REQUEST['searchfield']; 
$searchField = str_replace('+',' ', $searchField) ; 
$dbcolumn = "user_id"; 
$dbtable = "profiles"; 
$order = "user_id"; 

if ($searchField){ 
    if ($searchOption == "People"){ 
    $words = explode(' ', trim($searchField)); 
    $searchField = $words[0]; 
    $dbcolumn = "profile_display_name"; 
    $dbtable = "profiles P, user_roles U, roles R"; 
    $order = "profile_first_name"; 
    $criteria =  " P.user_id = U.user_id AND U.role_id = R.role_id 
        AND(`profile_display_name` LIKE '%$searchField%' 
        OR `profile_first_name` LIKE '%$searchField%' 
        OR `profile_last_name` LIKE '%$searchField%' 
        OR `profile_email` LIKE '%$searchField%' 
        OR `profile_state` LIKE '%$searchField%' 
        OR `profile_zip_code` LIKE '%$searchField%' 
        OR `business_summary` LIKE '%$searchField%')"; 
    } 
    //focus here folks (my comment to readers, not actual part of code 
    else if ($searchOption == "Jobs"){ 
    $dbcolumn = "job_title"; 
    $dbtable = "job_postings"; 
    $order = "`created_date` DESC"; 
    $criteria = "(`job_title` LIKE '%$searchField%' 
    OR `job_description` LIKE '%$searchField%' 
    OR `client_name` LIKE '%$searchField%' 
    OR `city` LIKE '%$searchField%' 
    OR `state_abbr` LIKE '%$searchField%' 
    OR `zipcode` LIKE '%$searchField%') 
    AND `job_status` = 'Open'"; 
    } 
    else if($searchOption == "News"){ 
    $dbcolumn = ""; 
    $dbtable = ""; 
    $order = ""; 
    $criteria = "1"; 
    } 

    //Pagination 
if($dbtable){ 
    $rs = mysql_query("SELECT * FROM $dbtable WHERE $criteria"); 
    $no_of_rec = mysql_num_rows($rs); 
    $page = ($_REQUEST['page'])? $_REQUEST['page'] : 1; 
    $no_of_pages = ceil($no_of_rec/$limit); 
    $offset = ($page - 1)*$limit; 

    echo "pagination #rows: $no_of_rec "; 
} 
} 

// If the user enters a value in the search 
if ($searchField){ 
    $resultcount = 0; 
    if($dbtable) { 
    // Search query executes 
    $query = "SELECT * FROM $dbtable WHERE $criteria "; 
    $query .= "ORDER BY $order "; 
    $query .= "LIMIT $offset, $limit"; 
    $result = mysql_query($query) or die(mysql_error()); 
    $resultcount = mysql_numrows($result); 

    echo "query: $query "; 
    echo "result: $result "; 
    echo "result count: $resultcount ";  
} 

if ($resultcount <= 0){ 
    $allResults[] = "No match found"; 
} 
else{ 
// Get search results from database 
    while ($row = mysql_fetch_array($result)){ 
$allResults[]=$row; 
    } 

} 
} 
    else{ 
    $allResults[] = "No value entered"; 
    } 
    ?> 

这里是回声报表显示： pagination #rows: 0 query: SELECT * FROM job_postings WHERE (`job_title` LIKE '%Help Wanted%' OR `job_description` LIKE '%Help Wanted%' OR `client_name` LIKE '%Help Wanted%' OR `city` LIKE '%Help Wanted%' OR `state_abbr` LIKE '%Help Wanted%' OR `zipcode` LIKE '%Help Wanted%') AND `job_status` = 'Open' ORDER BY `created_date` DESC LIMIT 0, 5 result: Resource id #36 result count: 0

（我留下回声打印输出，因此您可以看到我看到的以及我如何看到它）。

当我在MySQL和phpMyAdmin中运行查询时，我得到了我正在查找的行。

有人可以解释为什么mysql_numrows（）认为有0个结果吗？

我检查过PHP.net，我也搜索了这个。到目前为止没有运气。

非常感谢。

Answer 1

有这行

$resultcount = mysql_numrows($result); 

，你应该调用mysql_num_rows（）

您可以使用此代码或者

$isExist = mysql_query("Select count(id) from ..."); 
$r = mysql_fetch_array($isExist); 
if($r['COUNT(id)'] > 0){ 
//item exists 
}else{ 
//item doesnt exist 
}