我试图使用功能的strstr像这样:测试返回的strstr有效的指针
const char * pInicio = strstr(origem, chave);
if (pInicio != NULL) ...
出乎预期的,当我做“如果”测试编译器会抛出一个访问位置冲突异常。每次尝试获取某个字符串中不存在的关键字时都会发生。
调用堆栈是:
ntdll.dll!779315de()
[Os quadros abaixo podem estar incorretos e/ou ausentes, nenhum símbolo foi carregado para ntdll.dll]
ntdll.dll!779315de()
ntdll.dll!7792014e()
> msvcr100d.dll!_output_l(_iobuf * stream, const char * format, localeinfo_struct * plocinfo, char * argptr) Linha 2361 + 0xa bytes C++
cccccccc()
产量为:
Exceção de primeira chance em 0x0f8620a7 (msvcr100d.dll) no TestesApp.exe: 0xC0000005: Violação de acesso ao ler o local 0x00000001.
Exceção sem-tratamento em 0x779315de no TestesApp.exe: 0xC0000005: Violação de acesso ao ler o local 0x00000001.
右键异常之前,变量值分别为:
- 蔡夫:0x00196f64 “$ GNGSA”键入:char *
- Origem:0x00196840“$ GPRMC,000651.082,V ,,,,,,, 19 1210 ,,, N * 4F $ GPGGA,000652.091 ,,,,, 0,00 ,,, M,0.0,M ,, 0000 * 5F $ GPGSA,A,1 ,,,,,,,,,,,, ,,, * 1E”类型:常量字符*
- pInicio:00000000无效>类型:常量字符*
链接器命令行是:
/OUT:"C:\Users\Leandro\documents\visual studio 2010\Projects\TestesApp\Debug\TestesApp.exe" /INCREMENTAL /NOLOGO "kernel32.lib" "user32.lib" "gdi32.lib" "winspool.lib" "comdlg32.lib" "advapi32.lib" "shell32.lib" "ole32.lib" "oleaut32.lib" "uuid.lib" "odbc32.lib" "odbccp32.lib" /MANIFEST /ManifestFile:"Debug\TestesApp.exe.intermediate.manifest" /ALLOWISOLATION /MANIFESTUAC:"level='asInvoker' uiAccess='false'" /DEBUG /PDB:"C:\Users\Leandro\documents\visual studio 2010\Projects\TestesApp\Debug\TestesApp.pdb" /SUBSYSTEM:CONSOLE /PGD:"C:\Users\Leandro\documents\visual studio 2010\Projects\TestesApp\Debug\TestesApp.pgd" /TLBID:1 /DYNAMICBASE /NXCOMPAT /MACHINE:X86 /ERRORREPORT:QUEUE
也是C/C++命令行是
/ZI /nologo /W3 /WX- /Od /Oy- /D "WIN32" /D "_DEBUG" /D "_CONSOLE" /D "_UNICODE" /D "UNICODE" /Gm /EHsc /RTC1 /GS /fp:precise /Zc:wchar_t /Zc:forScope /Fp"Debug\TestesApp.pch" /Fa"Debug\" /Fo"Debug\" /Fd"Debug\vc100.pdb" /Gd /analyze- /errorReport:queue
在此之后,我尝试测试指针,如果它为空。 那是我现在的问题,该如何解决?
此致敬礼!
看起来不像它在这个代码中。你确定'strstr'的参数是有效的吗? – 2013-03-26 18:08:22
你确定错误发生在'if'行吗? – Barmar 2013-03-26 18:09:53
如果您从strstr()获得访问冲突,您传入的地址无效,或者它们引用的字符串未终止。我建议你在*结论上面的代码有问题之前验证两个条件*。 – WhozCraig 2013-03-26 18:20:12