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我使用xmlpullparser在android系统解析的XML文档的样子:解析XML XmlPullParser安卓
<top>
<category>
<name></name>
<desc></desc>
<songs>
<song>
<clip></clip>
<thumb></thumb>
</song>
<song>
<clip></clip>
<thumb></thumb>
</song>
</songs>
</category>
</top>
我尝试这样做:
while (eventType != XmlPullParser.END_DOCUMENT && !done){
String name = null;
switch (eventType){
case XmlPullParser.START_DOCUMENT:
categoriesSong = new ArrayList<TopMousika>();
break;
case XmlPullParser.START_TAG:
name = parser.getName();
if (name.equalsIgnoreCase(CATEGORY)){
currentCategory = new TopMousika();
currentCategory.setId(parser.getAttributeValue(0));
currentCategory.setId(parser.getAttributeValue(1));
} else if (currentCategory != null){
if (name.equalsIgnoreCase(NAME)){
currentCategory.setName(parser.nextText());
} else if (name.equalsIgnoreCase(DESCRIPTION)){
currentCategory.setDescription(parser.nextText());
} else if (name.equalsIgnoreCase(THUMBNAIL)){
currentCategory.setThumbnail(parser.nextText());
} else if (name.equalsIgnoreCase(SONGS)){
songs = new ArrayList<SongMousika>();
if(name.equalsIgnoreCase(SONG)){
currentSong = new SongMousika();
currentSong.setId(parser.getAttributeValue(0));
Log.d("TEST", "OK");
songs.add(currentSong);
} else if (name.equalsIgnoreCase(TITLE)){
Log.d("TEST", "OK2");
currentSong.setTitle(parser.nextText());
} else if (name.equalsIgnoreCase(SINGER)){
currentSong.setTitle(parser.nextText());
} else if (name.equalsIgnoreCase(THUMBNAIL)){
currentSong.setTitle(parser.nextText());
} else if (name.equalsIgnoreCase(PUBLICATION_DATE)){
currentSong.setTitle(parser.nextText());
} else if (name.equalsIgnoreCase(CLIP)){
currentSong.setTitle(parser.nextText());
}
currentCategory.setSongs(songs);
}
}
break;
case XmlPullParser.END_TAG:
name = parser.getName();
if (name.equalsIgnoreCase(CATEGORY) &&
currentCategory != null){
currentCategory.setSongs(songs);
categoriesSong.add(currentCategory);
} else if (name.equalsIgnoreCase(TOP)){
done = true;
}
break;
}
eventType = parser.next();
}
,但我不能找回我的歌曲列表。
任何人都可以帮我吗?
谢谢您的回答,我已经按照在IBM developerWorks上[链接](例子http://www.ibm.com/developerworks/opensource/library/x -android /) – wael
@wael:不,你没有。尝试找到一个例子,在那里他们检查'name'是否等于一个值,然后*在该条件下*检查'name'是否等于另一个值。他们检查'currentMessage'为空,并检查其中的各种名称,但这不是一回事。你现在明白为什么它不起作用吗? –
请您解释更多关于**您需要不断地拉动XML并对循环中的每个元素名称作出不同的反应** – wael