安卓：XML解析问题

林能够pasre和使用下面的方法显示在这个page的XML ..安卓：XML解析问题

private void loadTopMoversData() { 
    ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>(); 
    try { 
     String xml = XMLfunctions.getXML(TOPMOVERS_XML); 
     Document doc = XMLfunctions.XMLfromString(xml); 
     NodeList nodes = doc.getElementsByTagName("scrip"); 

     for (int i = 0; i < nodes.getLength(); i++) {  
      HashMap<String, String> map = new HashMap<String, String>();  

      Element e = (Element)nodes.item(i); 
      map.put("name", XMLfunctions.getValue(e, "name")); 
      map.put("currprice", XMLfunctions.getValue(e, "currprice")); 
      map.put("percentage", XMLfunctions.getValue(e, "percentage")); 
      map.put("code", XMLfunctions.getValue(e, "code")); 
      mylist.add(map); 

      Log.i("tag", XMLfunctions.getValue(e, "headline") + " " + XMLfunctions.getValue(e, "time")); 
     } 
    }

但是我无法解析用同样的方法在此page的XML，但适当的标签。我究竟做错了什么？

private void loadNewsData() { 
    ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>(); 
    try { 

     String xml = XMLfunctions.getXML(NEWS_XML); 
     Document doc = XMLfunctions.XMLfromString(xml); 
     NodeList nodes = doc.getElementsByTagName("data"); 
     ArrayList<String> links = new ArrayList<String>(); 
     for (int i = 0; i < nodes.getLength(); i++) { 
      Element e = (Element)nodes.item(i); 

      HashMap<String, String> map = new HashMap<String, String>();  
      map.put("headline", XMLfunctions.getValue(e, "headline")); 
      map.put("link", XMLfunctions.getValue(e, "link")); 
      map.put("time", XMLfunctions.getValue(e, "time")); 
      links.add(XMLfunctions.getValue(e, "link")); 
      mylist.add(map);    

      Log.i("tag", XMLfunctions.getValue(e, "headline") + " " + XMLfunctions.getValue(e, "time")); 
     } 

    } catch (Exception e) { 
     Log.e("tag", e.getMessage()); 
    } 
}`

这是我XmlFunctions.java

public class XMLfunctions { 

public final static Document XMLfromString(String xml){ 

    Document doc = null; 

    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); 
    try { 

     DocumentBuilder db = dbf.newDocumentBuilder(); 

     InputSource is = new InputSource(); 
     is.setCharacterStream(new StringReader(xml)); 
     doc = db.parse(is); 

    } catch (ParserConfigurationException e) { 
     System.out.println("XML parse error: " + e.getMessage()); 
     return null; 
    } catch (SAXException e) { 
     System.out.println("Wrong XML file structure: " + e.getMessage()); 
     return null; 
    } catch (IOException e) { 
     System.out.println("I/O exeption: " + e.getMessage()); 
     return null; 
    } 

    return doc; 

} 

public final static String getElementValue(Node elem) { 
    Node kid; 
    if(elem != null){ 
     if (elem.hasChildNodes()){ 
      for(kid = elem.getFirstChild(); kid != null; kid = kid.getNextSibling()){ 
       if(kid.getNodeType() == Node.TEXT_NODE ){ 
        return kid.getNodeValue(); 
       } 
      } 
     } 
    } 
    return ""; 
} 

public static String getXML(String webURL){  
     String line = null; 

     try { 

      DefaultHttpClient httpClient = new DefaultHttpClient(); 
      HttpPost httpPost = new HttpPost(webURL); 

      HttpResponse httpResponse = httpClient.execute(httpPost); 
      HttpEntity httpEntity = httpResponse.getEntity(); 
      line = EntityUtils.toString(httpEntity); 

     } catch (UnsupportedEncodingException e) { 
      line = "<results status=\"error\"><msg>Can't connect to server</msg></results>"; 
     } catch (MalformedURLException e) { 
      line = "<results status=\"error\"><msg>Can't connect to server</msg></results>"; 
     } catch (IOException e) { 
      line = "<results status=\"error\"><msg>Can't connect to server</msg></results>"; 
     } 

     return line; 

} 

public static int numResults(Document doc){  
    Node results = doc.getDocumentElement(); 
    int res = -1; 

    try{ 
     res = Integer.valueOf(results.getAttributes().getNamedItem("count").getNodeValue()); 
    }catch(Exception e){ 
     res = -1; 
    } 

    return res; 
} 

public static String getValue(Element item, String str) {  
    NodeList n = item.getElementsByTagName(str);   
    return XMLfunctions.getElementValue(n.item(0)); 
} 
}

有它的东西做的xml文件？请帮忙。由于

编辑： 可有人也请告诉我如何解析与“&” XML在其与此解析器？

来源

2011-04-19 Rohith Nandakumar

你得到什么错误，而分析第二个文件？ – Olegas 2011-04-19 10:21:47

我可以直接说出您解析XML的方式，并且我可以建议您使用像Simple这样的基于注释的解析器。我甚至写了一篇关于如何在这里使用它的博客文章：http://massaioli.homelinux.com/wordpress/2011/04/21/simple-xml-in-android-1-5-and-up/ – 2011-04-21 04:55:09

我想通了这个问题。在XMLfunctions.java，它检查是否节点是TEXT_NODE，显然在XML节点不是一个..

if(kid.getNodeType() == Node.TEXT_NODE ){ 
       return kid.getNodeValue(); 
}

所以，我删除了条件，现在可以正常工作。由于

来源

2011-04-19 11:30:06

您可能需要重新检查你的XML节点名，区分大小写。还检查你的链接数组是否正常？

来源

2011-04-19 10:28:15 kingcomtech

第二进是不是正确的XML。正如你认为&没有正确逃脱。它需要像这样：&请参阅here和here。

然而，有些解析器可以容忍这一点，就不会出错了。如果这些解析器不是一个。

你既可以尝试一些不同的解析器或者你可以尝试修复与饲料发现你开始解析之前更换。如果你这样做，你必须要小心，不要再逃避已经被转义字符，否则你会最终的东西是这样的：&amp;

来源

2011-09-12 08:59:01 Robert

安卓：XML解析问题

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