在StringBuilder对象中查找多个字母

Question

我正在尝试创建一个hangman程序...以及其他问题，我似乎无法找到或创建方法查找更多然后发生一个字母并替换所有发现的事件。我一直在用findAndReplace（）方法来解决这个问题......它没有奏效。请谁能帮助我

public class Hangman { 


static Scanner sc = new Scanner(System.in); 
     static final int MAXTRYS = 10; 
     static int numError = 0; 
     static boolean FINSHED = false; 
     String s; 
     String input; 
     String tW; 
     int pos; 


     public static void main(String[] args) { 
      System.out.println("Welcome to the Hangman App" + "\n"); 
      String s = answerKey(); 
      StringBuilder AnswerKey = dashReplace(s); 




      while(!FINSHED && numError < MAXTRYS){ 
      //get user input and cast to char 
      System.out.println("Enter an Letter: "); 
      String input = sc.nextLine(); 
      char ch = input.charAt(0); 


      int pos = findAndReplace(s, AnswerKey, input, ch); 
      int index = AnswerKey.indexOf("-"); 
      if(pos == -1){ 
       numError++; 
       continue; 
      }else if(index == -1){ 
       FINSHED = true; 
       System.out.println("you won!"); 
      } 
      } 

     } 


     public static int findAndReplace(String s, StringBuilder AnswerKey, 
       String input, char ch) { 
      //find position of user input and replace 
      int pos = s.indexOf(input); 
      AnswerKey.setCharAt(pos, ch); 
      // while(pos > 0) { 
      // AnswerKey.setCharAt(pos, (char) (ch+1)); 
      //} 
      System.out.println(AnswerKey); 
      return pos; 
     } 


     public static StringBuilder dashReplace(String s) { 
      //replace non-white space char with dashes and creates StringBuilder Object 
      String tW = s.replaceAll("\\S", "-"); 
      System.out.print(tW + "\n"); 
      StringBuilder AnswerKey = new StringBuilder(tW); 
      return AnswerKey; 
     } 


     public static String answerKey() { 
      //get random array element 
      String array[] = new String[10]; 
      array[0] = "Hamlet"; 
      array[1] = "Mysts of Avalon"; 
      array[2] = "The Iliad"; 
      array[3] = "Tales from Edger Allan Poe"; 
      array[4] = "The Children of Hurin"; 
      array[5] = "The Red Badge of Courage"; 
      array[6] = "Of Mice and Men"; 
      array[7] = "Utopia"; 
      array[8] = "Chariots of the Gods"; 
      array[9] = "A Brief History of Time"; 

      ArrayList<String> list = new ArrayList<String>(Arrays.asList(array)); 
      Collections.shuffle(list); 
      String s = list.get(0); 
      //for testing 
      System.out.println(s); 
      return s; 
     } 

} 

Answer 1

一典型的“查找和替换”循环如下所示：

// Search starts at pos+1, so we set pos to -1 to start search at zero 
int pos = -1; 
// We'll break out of the loop when there are no further matches 
while (true) { 
    // Look for the desired character starting one character past the pos 
    pos = s.indexOf(input, pos+1); 
    // If the character is not found, end the loop 
    if (pos < 0) break; 
    // Otherwise, replace the character 
    s.setCharAt(pos, ch); 
} 

见注释在上面的代码来了解世界卫生大会t正在发生。

Answer 2

最简单的办法似乎是改变你StringBuilder为String，使用replace()方法，然后只用更换一个新的StringBuilder：

answerKey = new StringBuilder(answerKey.toString().replace(charToReplace, newChar));