我的for循环似乎是不可见的

-1

我试图让程序计算出前四个完美数字。它编译，但是当我运行该程序时，for循环似乎是不可见的。就像我查看调试器时一样，它看起来只是跳过了for循环，变量不存在。我的for循环似乎是不可见的

public static void main(String[] args) 
{ 
    int pNum = 2; // starting number to check 
    int sum = 0; 

    for (int count = 1; count <= 4; count++) 
    { 
     for (int factor = 1; factor < pNum; factor++) 
     { 
      if (pNum % factor == 0) 
       sum += factor; 
     } 

     if (pNum == sum) 
     { 
      System.out.println(pNum + " is a perfect number."); 
      count++; 
     } 

     pNum++; sum = 0; 
    } 
}

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2011-09-07 CowZow

现在，它的工作原理。非常感谢！编辑：克里斯的评论似乎已经消失了（我是否意外删除它？），但这是因为我递增了两次计数++。 – CowZow

所以我用一个while循环替换了第一个for循环 – CowZow

count = 1, pNum = 2, sum = 0 
factor = 1, sum = 0 
count = 2, pNum = 3, sum = 0 
factor = 1, sum = 0 
factor = 2, sum = 1 
count = 3, pNum = 4, sum = 0 
factor = 1, sum = 0 
factor = 2, sum = 1 
factor = 3, sum = 3 
count = 4, pNum = 5, sum = 0 
factor = 1, sum = 0 
factor = 2, sum = 1 
factor = 3, sum = 1 
factor = 4, sum = 1

来源

2011-09-07 23:12:57

我觉得你的调试器出毛病了，尝试printoutput来检查循环工作

for(int count = 1; count <= 4; count++){ 
    System.out.println("count:"+count);

来源

2011-09-07 23:10:09

我的for循环似乎是不可见的

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