我试图创建一个带有4列项目,数量,成本和金额的HTML表单...全部在一个PHP文件中。如何从MySQL中检索数据并将其显示在文本字段中
物品栏是选择标记,从MySQL表,现在基础上的物品1的成本必须在费用文本标记,值的正常工作
收集数据。
下面是我的代码:
</tr>
<tr> <td align="left">
<?php
$user_name = "won";
$password = "[email protected]";
$database = "won";
$server = "127.0.0.1";
$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);
if ($db_found) {
$result = mysql_query("SELECT item FROM test ");
echo "<select>";
echo "<option value=''>Select Item</option>";
while($row = mysql_fetch_array($result))
{
echo "<option value='item1' id='item1' name='item1'>" .$row['item']. "</option>";
}
echo "</select>";
}
mysql_close($db_handle);
?>
</td>
<td align="left"><input type="text" id="qty1" name="qty1"> </td>
<td align="left"><input type = "text" onclick = "myFunction1()" id="row['cost']" > </td>
<td align="left"><input type="text" id="amount1" name="amount1" value=0> </td>
</tr>
*************************************************************************
The following is the function :
function myFunction1()
{
<?php
$user_name = "won";
$password = "[email protected]";
$database = "won";
$server = "127.0.0.1";
$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);
if ($db_found) {
$result = mysql_query("SELECT cost FROM test where item='$item1' ");
$row = mysql_fetch_array($result);
}
mysql_close($db_handle);
?>
}