2012-03-31 70 views
9

我正在研究一段时间来查找信息如何使用PyQT执行多线程程序,更新GUI以显示结果更新MultiThreaded PyQT中的GUI元素

我习惯于通过示例进行学习,但找不到(是的,我正在寻找几周)任何使用多线程程序的简单示例,可以执行诸如连接到www站点列表(5个线程)等简单任务,只需打印带响应代码的处理过的网址即可。

任何人都可以共享代码或发送给我很好的教程,这样的程序解释?

+0

哎,我没试过PyQt的,但我在pygtk的使用多线程。在pygtk中,gobject通常用于这样做。你应该搜索pyQt类似的东西。 – Froyo 2012-03-31 16:36:28

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另请参阅http://stackoverflow.com/questions/11265812/pyside-pyqt-starting-a-cpu-intensive-thread-hangs-the-whole-application,http://stackoverflow.com/questions/16879971/example -of-the-right-way-to-use-qthread-in-pyqt,http://stackoverflow.com/questions/6783194/background-thread-with-qthread-in-pyqt或http://stackoverflow.com/questions/20752154/pyqt-connecting-a-signal-to-a-slot-to-start-a-background-operation – Trilarion 2015-01-07 09:44:15

回答

22

这里有一些非常基本的例子。

您可以将对GUI元素的引用传递给线程,并在线程中更新它们。

import sys 
import urllib2 

from PyQt4 import QtCore, QtGui 


class DownloadThread(QtCore.QThread): 
    def __init__(self, url, list_widget): 
     QtCore.QThread.__init__(self) 
     self.url = url 
     self.list_widget = list_widget 

    def run(self): 
     info = urllib2.urlopen(self.url).info() 
     self.list_widget.addItem('%s\n%s' % (self.url, info)) 


class MainWindow(QtGui.QWidget): 
    def __init__(self): 
     super(MainWindow, self).__init__() 
     self.list_widget = QtGui.QListWidget() 
     self.button = QtGui.QPushButton("Start") 
     self.button.clicked.connect(self.start_download) 
     layout = QtGui.QVBoxLayout() 
     layout.addWidget(self.button) 
     layout.addWidget(self.list_widget) 
     self.setLayout(layout) 

    def start_download(self): 
     urls = ['http://google.com', 'http://twitter.com', 'http://yandex.ru', 
       'http://stackoverflow.com/', 'http://www.youtube.com/'] 
     self.threads = [] 
     for url in urls: 
      downloader = DownloadThread(url, self.list_widget) 
      self.threads.append(downloader) 
      downloader.start() 

if __name__ == "__main__": 
    app = QtGui.QApplication(sys.argv) 
    window = MainWindow() 
    window.resize(640, 480) 
    window.show() 
    sys.exit(app.exec_()) 

编者按: Qt控件不是线程安全的,不应由任何线程,但主线程(见Qt documentation了解详细信息)进行访问。正如本答案的第二部分所示,使用线程的正确方法是通过信号/插槽。


另外,您可以使用信号和插槽来分离gui和网络逻辑。

import sys 
import urllib2 

from PyQt4 import QtCore, QtGui 


class DownloadThread(QtCore.QThread): 

    data_downloaded = QtCore.pyqtSignal(object) 

    def __init__(self, url): 
     QtCore.QThread.__init__(self) 
     self.url = url 

    def run(self): 
     info = urllib2.urlopen(self.url).info() 
     self.data_downloaded.emit('%s\n%s' % (self.url, info)) 


class MainWindow(QtGui.QWidget): 
    def __init__(self): 
     super(MainWindow, self).__init__() 
     self.list_widget = QtGui.QListWidget() 
     self.button = QtGui.QPushButton("Start") 
     self.button.clicked.connect(self.start_download) 
     layout = QtGui.QVBoxLayout() 
     layout.addWidget(self.button) 
     layout.addWidget(self.list_widget) 
     self.setLayout(layout) 

    def start_download(self): 
     urls = ['http://google.com', 'http://twitter.com', 'http://yandex.ru', 
       'http://stackoverflow.com/', 'http://www.youtube.com/'] 
     self.threads = [] 
     for url in urls: 
      downloader = DownloadThread(url) 
      downloader.data_downloaded.connect(self.on_data_ready) 
      self.threads.append(downloader) 
      downloader.start() 

    def on_data_ready(self, data): 
     print data 
     self.list_widget.addItem(unicode(data)) 


if __name__ == "__main__": 
    app = QtGui.QApplication(sys.argv) 
    window = MainWindow() 
    window.resize(640, 480) 
    window.show() 
    sys.exit(app.exec_()) 
+0

我将分析这个例子。谢谢。 – Nuncjo 2012-04-01 13:28:38

+1

+1用于建议使用信号将线程从显示逻辑中分离出来。 – Whatang 2012-04-02 00:23:07

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示例非常棒,这正是我所寻找的,但是如何将线程数限制为5个同时工作? – Nuncjo 2012-04-07 13:55:12